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11Alexandr11 [23.1K]
3 years ago
9

Timothy spent $68 at Macy's. His purchases include a pair of jeans at $32 and 2 t-shirts at $x each. how much for each t-shirt.

Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

idk

Step-by-step explanation:

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Solve.<br><br> 5m + 7/2 = -2m + 5/2
crimeas [40]
5m + 7/2 = -2m + 5/2
5m + 2m = 5/2 - 7/2
7m = -1
m = -1/7 <==
8 0
3 years ago
Find the circumference of a circle that has a 25-inch radius. Use 3.14 to approximate π.
Sergio [31]

\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }

\large\underline{  \boxed{ \sf{✰\:Important\: point's }}}

  • ➣ Circle:- A two-dimensional geometric figure, a line, consisting of the set of all those points in a plane that are equally distant from a given point (center).
  • ➣ Circumference:- The line that bounds a circle or other two-dimensional figure

{ \rule{70mm}{2.9pt}}

★ also circumference of a circle is also known as it's perimeter

  • ➣To find circumference of circle when use formula

{ \boxed{✜\underline{  \boxed{ \sf{\: Circumference \:  of  \: circle= \: 2\pi \: r}}}✜}}

  • ➢ r = radius (25inch.)
  • ➢ value of π is 3.14

{ \rule{70mm}{2.9pt}}

\large\underline{  \boxed{ \sf{✰\: Let's\:solve }}}

\sf{➛ \: Circumference  \: of  \: circle = 2 \times 3.14 \times 25} \\ \sf{➛ \: Circumference  \: of  \: circle =2 \times 78.5} \\ \sf{➛ \: Circumference  \: of  \: circle =157inch}

★ Hence circumference of circle=157inch

\large\underline{  \boxed{ \sf{➪\:157inch. }}}

{ \rule{70mm}{2.9pt}}

Hope it helps !

4 0
2 years ago
Explain how to identify the terms of 3y - 4 - 5y
Yuliya22 [10]
Well the answer is -2y-4 but the different terms in this problem are 4 and 5y and 3y where 5y and 3y are like terms
8 0
3 years ago
Read 2 more answers
PLEASE HELP ME
balandron [24]

Answer:

  • The sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is <u>translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis</u>.

Explanation:

By inspection (watching the figure), you can tell that to transform the triangle XY onto triangle X"Y"Z", you must slide the former 5 units to the left, 1 unit down, and, finally, reflect it across the x-axys.

You can check that analitically

Departing from the triangle: XYZ

  • <u>Translation 5 units to the left</u>: (x,y) → (x - 5, y)

  • Vertex X: (-6,2) → (-6 - 5, 2) = (-11,2)
  • Vertex Y: (-4, 7) → (-4 - 5, 7) = (-9,7)
  • Vertex Z: (-2, 2) → (-2 -5, 2) = (-7, 2)

  • <u>Translation 1 unit down</u>: (x,y) → (x, y-1)

  • (-11,2) → (-11, 2 - 1) = (-11, 1)
  • (-9,7) → (-9, 7 - 1) = (-9, 6)
  • (-7, 2) → (-7, 2 - 1) = (-7, 1)

  • <u>Reflextion accross the x-axis</u>: (x,y) → (x, -y)

  • (-11, 1) → (-11, -1), which are the coordinates of vertex X"
  • (-9, 6) → (-9, -6), which are the coordinates of vertex Y""
  • (-7, 1) → (-7, -1), which are the coordinates of vertex Z"

Thus, in conclusion, it is proved that the sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.

7 0
3 years ago
Derive the equation of the parabola with the focus <br> is (-7,5) and the directrix of y=-11
Volgvan
So, notice, the focus point is at -7, 5, and the directrix is at y = -11.

keep in mind that the vertex is half-way between those two fellows, and the distance from the vertex to either one of them is "p" units, check the picture below.

with that focus point and that directrix, the half-way over the axis of symmetry will be -7, -3, that's where the vertex is at, and notice the distance "p", is 8 units.

since the parabola is opening upwards, "p" is positive 8.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;4p(x- h)=(y- k)^2&#10;\\\\&#10;\boxed{4p(y- k)=(x- h)^2}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ( h, k)\\\\&#10; p=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;h=-7\\&#10;k=-3\\&#10;p=8&#10;\end{cases}\implies 4(8)[y-(-3)]=[x-(-7)]^2&#10;\\\\\\&#10;32(y+3)=(x+7)^2\implies y+3=\cfrac{1}{32}(x+7)^2&#10;\\\\\\&#10;y=\cfrac{1}{32}(x+7)^2-3

8 0
3 years ago
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