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White raven [17]
3 years ago
11

What is the kinetic Energy of a 110 kg linebacker rushing towards his football

Mathematics
1 answer:
Leviafan [203]3 years ago
3 0

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

KE=\frac{1}{2} \times m v^{2}

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules

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Answer:

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Step-by-step explanation:

y=x^2-6x+3

This is written in the standard form of a quadratic function:

y=ax^2+bx+c

where:

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You need to convert this to vertex form:

y=a(x-h)^2+k

where:

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To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:

x=-\frac{b}{2a}

Using your original equation, identify the a, b, and c terms:

a=1\\\\b=-6\\\\c=3

Insert the known values into the equation:

x=-\frac{(-6)}{2(1)}

Simplify. Two negatives make a positive:

x=\frac{6}{2} =3

X is equal to 3 (3,y). Insert the value of x into the standard form equation and solve for y:

y=3^2-6(3)+3

Simplify using PEMDAS:

y=9-18+3\\\\y=-9+3\\\\y=-6

The value of y is -6 (3,-6). Insert these values into the vertex form:

(3_{h},-6_{k})\\\\y=a(x-3)^2+(-6)

Insert the value of a and simplify:

y=(x-3)^2-6

:Done

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Work Shown:

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x = 6.93

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