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3 years ago

Find the area or this triangle

Mathematics

1 answer:

Arlecino [84]3 years ago

3 0

Answer:

Area of triangle = 15 square units

Step-by-step explanation:

We need to find area of the triangle, given the vertices:

A=(4,0)

B=(1,5)

C=(7,5)

The formula used is: $Area\:of\:triangle=\frac{1}{2}(x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))$

We have: $x_1 =4, y_1 =0, x_2 =1, y_2=5, x_3=7 , y_3=5$

Putting values and finding area

$Area\:of\:triangle=\frac{1}{2}(x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))\\Area\:of\:triangle=\frac{1}{2}(4(5-5)+1(5-0)+7(0-5))\\Area\:of\:triangle=\frac{1}{2}(4(0)+1(5)+7(-5))\\Area\:of\:triangle=\frac{1}{2}(0+5-35)\\Area\:of\:triangle=\frac{1}{2}(-30)\\Area\:of\:triangle=-15$

We will be ignoring negative sign, because area of triangle is positive.

So, Area of triangle = 15

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Answer:

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Step-by-step explanation:

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A = 4 + 4*(4)

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3 years ago

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Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is

y=0.

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3 years ago

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4 years ago

F(x) = { -2x -1, x ≤ 2

Degger [83]

Answer:

Use the appropriate entry method for piecewise functions for the graphing calculator of interest.

Step-by-step explanation:

For Desmos, the entry looks like ...

f(x) = {x ≤ 2: -2x-1,-x+4}

_____

For a TI-84 calculator, the entry may look like ...

Y₁ = (-2X–1)(X≤2) + (-X+4)(X>2)

The symbols ≤ and > come from the TEST menu, which is the (2nd) shift of the MATH key.

Note that the function is the sum of the pieces, each piece multiplied by a test. For something like 0≤x<2, the multiplier would be a pair of tests:

... (0≤X)(X<2)

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4 years ago

Please fill in the blank

Katen [24]

Answer:

The independent variable is h

The dependent variable is P

Domain of h: 3<h<23

Range of h: 26<P<46

Step-by-step explanation:

Domain and Range of Functions

A function that is explicitly defined can have restrictions on its variables that guarantee its existence. For example, a function with a variable denominator must restrict the domain (values of the dependent variable) so, the denominator is never zero. Once determined the domain of the function, the range is made of all values the function can take.

We have a triangle with sides h,13, and 10. The perimeter of the triangle, called P is the sum of its sides

P=h+13+10=23+h

h is the independent variable, whose value modify the value of P, so P is the dependent value

Since h is the third side of the triangle, some restrictions apply. First, h cannot be less than the difference between 13 and 10, because it will produce an incomplete triangle. For example, if h=2, it won't be enough to bond the other vertices of the triangle with a line. So the minimum value of h is 3.

On the other hand, h cannot exceed the sum of the other sides, because in that case, they won't be long enough to reach the last vertex of the triangle. So h must be less than 23. It forms the restriction of the domain

3<h<23

As a consequence, the range will be restricted also.

Since P=23+h, we get h=P-23. Replacing in the above domain:

3<P-23<23

Adding 23, the range is revealed:

26<P<46

7 0

3 years ago

Read 2 more answers

Find the area or this triangle ​

Find the area or this triangle