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Nina [5.8K]
3 years ago
8

How do you write six times the quantity two x plus three y with numbers??

Mathematics
1 answer:
tresset_1 [31]3 years ago
3 0

Answer:

12x + 18y

Step-by-step explanation:

Lets first write the quantity "two x plus three y", this means, that we have x and y as unknowns. x is 2 times, so we have 2x; and y is 3 times, so he have 3y:

2x + 3y

Additionally we have that this quantity is six times, what means that it is multiplied by a number 6:

6(2x +3y)

If you like, we can apply the distributive property that means that given any three numbers a, b, c we have that a(b+c)=ab + ac. In our case a is 6, b is 2x and c is 3y. Thus, operating:

6(2x +3y) = 6*2x + 6*3y = 12x + 18y

So, "six times the quantity two x plus three y" is 12x + 18y

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The management team of a company with 10,000 employees is considering installing charging stations for electric cars in the comp
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Answer:

The 99 percent confidence interval for the proportion of all employees at the company who own an electric car is (0.0104, 0.0496).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In a random sample of 500 employees, 15 reported owning an electric car.

This means that n = 500, \pi = \frac{15}{500} = 0.03

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.03 - 2.575\sqrt{\frac{0.03*0.97}{500}} = 0.0104

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.03 + 2.575\sqrt{\frac{0.03*0.97}{500}} = 0.0496

The 99 percent confidence interval for the proportion of all employees at the company who own an electric car is (0.0104, 0.0496).

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2 years ago
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