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DedPeter [7]
3 years ago
15

3. Brenda's school is selling tickets to a spring musical. On the first day of

Mathematics
1 answer:
Natalija [7]3 years ago
4 0

Answer:

The Answer is that Senior Citizen Tickets cost: $4 and Child tickets cost: $7.

Step-by-step explanation:

Let s = the cost of senior citizen tickets

Let c = the cost of child tickets

The number of tickets sold for each type added together equals the sales for each day. Equations below:

Day 1

3s + 9c = $75

Solve for s:

3s = 75 - 9c

s = 25 - 3c

Day 2

8s + 5c = $67

By substitution:

8(25 - 3c) + 5c = 67

200 - 24c + 5c = 67

-19c = -133

c = -133 / -19 = $7 cost for child tickets.

Solve for s:

s = 25 - 3c

s = 25 - 3(7)

s = 25 - 21 = $4 cost for senior citizen tickets.

Proofs:

Day 1

3s + 9c = $75

3(4) + 9(7) = 75

12 + 63 = 75

75 = 75

Day 2

8s + 5c = $67

8(4) + 5(7) = 67

32 + 35 = 67

67 = 67

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
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Answer:

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Minimum value = - 36

Step-by-step explanation:

Given that

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From Lagrange multipliers

Δf = λ Δh

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Δf = λ Δh

So

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8 = 8  λ x                     -------------1

8 = 8 λ y                      ----  ------2

4 = 8 λ z                    ----------------3

From equation 1 ,2 and 3

Now by putting the value of x,y and z in the following equation

4 x² + 4 y² + 4 z² = 36

4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36

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So the value of λ is

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When λ = 1/2

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x= 2 , y = 2 , z=1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

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