The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.
Ideal gas behavior:
Suppose the initial volume of carbon dioxide gas is V = 3.5l
Initial pressure is P = 125 kPa
Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L
The final pressure of the gas is P'.
We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.
PV = P'V'
125 × 3.5 = P'× 2
P'= 218.75 kPa
Therefore, the final pressure is 218.5 kPa.
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6 x 10 =60
40 x 24=960
maybe
I REALLY DON'T KNOW
Answer:
1) 4
2) 1
3) -7
4) 13
Step-by-step explanation:
Instructions:
a) Subtract or add the slope from each side
( it doesn't matter which one you pick )
b) Subtract or add the # next to the slope from each side
( it doesn't matter which one you pick )
c) Divide Each number by the slope
d You have you answer
____________________________________________
1) 9x - 35 = - 7x + 29
+7x + 7x
_____________________
16x - 35 = 29
+ 35 +35
_____________________
16x = 64
_____________________
16 16
x = 4
2). - 2x - 2 = 9x - 13
+2x +2x
_____________________
- 2 = 11x - 13
+ 13 + 13
_____________________
11 = 11x
_____________________
11 11
1 = x
3). 3x + 29 = - 5x - 27
+5x + 5x
_____________________
8x + 29 = - 27
-29 -29
_____________________
8x = -56
_____________________
8 8
x = -7
4). x - 11 = 3x - 37
- x - x
______________________
-11 = 2x - 37
+37 +37
______________________
26 = 2x
_______________________
2 2
13 = x
Hope this helps! (:
The given equation is in the point-slope form. The slope can be obtained by simple identification of the parts of the equation. This is shown below:
Given equation:
(y - 3) = -2 (x - 4)
y - y1 = m(x - x1)
Where slope, m = -2
The slope of a line perpendicular to the line CD is the negative reciprocal of the slope of the line CD. Therefore:
Slope = 1/2
The last option is your answer.
Line DE being parallel to Line AC means the angles that are connected (for lack of a better word) to the endpoints would be the same degree.
