I need this answer asap

PLEASE HELP!! I know I need to factor but I’m confused…

Veseljchak [2.6K]

Answer:

x = 16

Step-by-step explanation:

Given a tangent and a secant from an external point to a circle, then

The product of the external part and the whole of the secant is equal to the square of the tangent, that is

9(9 + x) = 15²

9(9 + x) = 225 ( divide both sides by 9 )

9 + x = 25 ( subtract 9 from both sides )

x = 16

5 0

3 years ago

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I need help with the last 2 I need the next 3 in the sequence and the nth term

kkurt [141]

Answer:

f. the sequence goes by the half of the previous number.

= 16, 8, 4, 2, 1, 1/2, 1/4, 1/8...

g. the sequence goes by adding the consecutive odd number added to the previous number.

first number= 3.

second number= 3+3

= 6

third number= 6+5

= 11

fourth number= 11+7

= 18

fifth number= 18+9

= 27

sixth number= 27+11

= 38

seventh number= 38+13

= 51, etc.

= 3, 6, 11, 18, 27, 38, 51...

7 0

3 years ago

Help!! PLease someone

lawyer [7]

It is 5 you just have to count

7 0

3 years ago

Gabrielle's age is two times Mikhail's age. The sum of their ages is 81. What is Mikhail's age?

Darya [45]

Answer:

27

Step-by-step explanation:

Let g be Gabrielle's age and m be Mikhail's age.

We can turn the statements the problem gives us into mathematical expressions to help us solve.

Gabrielle's age is two times Mikhail's age:

g = 2m

The sum of their ages is 81:

g + m = 81

This gives us a system of equations that will allow us to solve for Gabrielle's age.

g + m = 81

(2m) + m = 81

3m = 81

m = $\frac{81}{3}$

m = 27

If we need to solve for Gabrielle's age, we can do the following.

g = 2m

2(27) = g

54 = g

g = 54

Mikhail's age is 27.

Gabrielle's age is 54.

8 0

2 years ago

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An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago