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Ostrovityanka [42]
3 years ago
6

Andrew and Sarah are tracking the number of steps they walk. Andrew records that he can walk 6000 steps in 50 minutes. Sarah wri

tes the equation y=118x where y is the number of steps and x is the number of minutes she walks, to describe her step rate.
Mathematics
1 answer:
Leni [432]3 years ago
5 0

Answer:

Andrew walks more steps than Sarah.

Step-by-step explanation:

The question is incomplete. The complete question is :

Andrew and Sarah are tracking the number of steps they walk. Andrew records that he can walk 6000 steps in 50 minutes. Sarah writes the equation y=118x, where y is the number of steps and x is the number of minutes she walks, to describe her step rate. This week, Andrew and Sarah each walk for a total of 5 hours. Who walks more steps?

Solution:

Given:

Andrew walks 6000 steps in 50 minutes.

Number of steps Sarah walks is given by the equation :

y=118x

where y is the number of steps and x is the number of minutes she walks.

Finding the number of steps each walks in 5 hours.

Total number of minutes in 5 hours = 5\times 60 = 300\ min

For Andrew:

Using unitary method:

If in 50 minutes Andrew walks = 6000 steps.

In 1 minute he will walk = \frac{6000}{50} = 120 steps

In 300 minutes he will walk = 120\times 300 = 36000 steps

Thus, Andrew will walk 36,000 steps in 5 hours.

For Sarah:

We will plugin x=300 in the equation and solve for y.

We have:

y=118(300)

∴ y=35400

Thus, Sarah will walk 35,400 steps in 5 hours.

Therefore, Andrew walks more steps than Sarah as 36,000>35,400.

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Find the value of the third quartile (the median of the upper half of the data set). 52, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61,
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Answer:

64.5

Step-by-step explanation:

You understand the question, and already have the numbers in order, you're almost there!

So you need to find the median first so you can divide the data set into the upper and lower halves. The median, as you probably know, is the center of the data. What I do for this is list all the numbers out in order, like you've already done, and start crossing them out, one at a time, alternating the sides. I'll show you what I mean. (I'm using underline because there's no strikethrough.)

<u>52</u>, 54, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, 70, <u>72</u>

<u>52, 54</u>, 55, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, 68, <u>70, 72</u>

<u>52, 54, 55</u>, 55, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, 65, <u>68, 70, 72</u>

<u>52, 54, 55, 55</u>, 57, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, 65, <u>65, 68, 70, 72</u>

<u>52, 54, 55, 55, 57</u>, 58, 59, 59, 61, 61, 61, 62, 63, 63, 64, <u>65, 65, 68, 70, 72</u>

...and so on, until you have:

<u>52, 54, 55, 55, 57, 58, 59, 59, 61</u>, 61, 61, <u>62, 63, 63, 64, 65, 65, 68, 70, 72</u>

Because there's an even number of numbers, the median is the mean of the middle two numbers. Luckily, though, the two numbers in the middle are the same:61. Mean is calculated by adding the terms and dividing by the number of terms. In this case:

(61+61)/2

=61

(You didn't really have to do this mean step, but I'll explain later.)The median is 61. Another way you could have done this is by just counting the number of terms (20) and finding the middle one. Again, since there's no middle one, you'd have to find the mean.

Since you're looking for the third quartile and not the median, you didn't exactly have to do that step. I just wanted to explain how to calculate the median, since you'll have to do it in the next step. All we had to do here was divide the data set into the halves, so we used that visual demonstration by underlining the numbers one at a time. We didn't have to find the mean, we could have split the set down the middle instead.

<u>52, 54, 55, 55, 57, 58, 59, 59, 61, </u>61, | 61, <u>62, 63, 63, 64, 65, 65, 68, 70, 72</u>

                                                             ^median/half-way point

We could have also divided the number of terms (20) by 2 (because halves, 2 parts) to get 10 and used the upper 10 values of the set, but I don't know, the crossing out method helps me. Anyway, now we have to look at just the upper 10 values:

61, 62, 63, 63, 64, 65, 65, 68, 70, 72

And you repeat the process! (I'm not going to show the underlining though lol)

There are 10 terms, so the median is between the 5th and the 6th. (10/2=5)

<u>61, 62, 63, 63</u>, 64, 65, <u>65, 68, 70, 72</u>

This is what I was talking about, there are an even number of values in the upper half of the data set as well, so we have to find the mean of the middle 2: 64 and 65.

 (64+65)/2

=129/2

=64.5

That's your final answer. Hope I could help you!

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