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2 years ago

Answer plss plss pslsss

Mathematics

1 answer:

OverLord2011 [107]2 years ago

8 0

Answer:

The answers are:

1. C

2.D

3. A

4. C

5. D

6. A

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We are given expression: $(2x^4y^5)^{3/8}$

Let us distribute 3/8 over exponents in parenthesis, we get

$(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})$

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$(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )$

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3 years ago

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3 years ago

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Step-by-step explanation:

The given expression 2x^2 + 3x +3 cannot be factored.

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