Answer:
x=17/3, y=59. (17/3, 59).
Step-by-step explanation:
y=6x+25
y=12x-9
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6x+25=12x-9
12x-6x-9=25
6x-9=25
6x=25+9
6x=34
x=34/6=17/3
y=12(17/3)-9=4*17-9=68-9=59
Answer:

Step-by-step explanation:
P, A, and R are collinear.
PR = 54


To solve for the numerical length of PR, let's generate an equation to find the value of x.
According to the segment addition postulate:

(substitution)
Solve for x

Combine like terms


Add 2 to both sides


Divide both sides by 7



Plug in the value of x into the equation


Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
Answer:
Step-by-step explanation:
No but it is close. (4x +13x +10) factors into
(4x + 5)(x + 2)
So (x + 2) is a factor along with (4x + 5)
Answer:
No it is not a good sample because if a person works full time then he would be at work around that time.
Step-by-step explanation: