Sin(90 + θ)
By addition angle formula for sine.
sin90cosθ + cos90sinθ
1*cosθ + 0*sinθ
cosθ + 0
= cosθ
sin(90 + θ) = cosθ
The answer would be A because I did the math :)
So obviously the 20N pulls more than the 5N. Friction opposes direction of motion, so the 5N opposes the 20N and the two forces are against each other.
Net force would be in the direction of the 20N force: 20N - 5N = 15N.
Force = mass*acceleration
15 = (5)*acceleration
acceleration = 3m/s^2
Answer:
The linear velocity of the racquet at the point of contact with the ball is 6 m/s.
Explanation:
Given;
angular velocity of the racquet, ω = 12 rad/s
distance of strike, r = 0.5 m
The linear velocity of the racquet at the point of contact is given by;
V = ωr
V = (12)(0.5)
V = 6 m/s
Therefore, linear velocity of the racquet at the point of contact with the ball is 6 m/s.
