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3 years ago

Altitude is the angle measured above ____. North Pole horizon equator zenith

Physics

2 answers:

juin [17]3 years ago

5 0

Altitude is the angle measured above the horizon

Ierofanga [76]3 years ago

4 0

The angle measured above the horizon.

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Ce 1. A satellite does not need any energy to revolue around the planet. Why?

olasank [31]

Hope this helped! i’m not sure if it’s right. it honestly bored so i’m answering questions.

3 0

2 years ago

A spherical bowling ball with mass m = 3.4 kg and radius R = 0.113 m is thrown down the lane with an initial speed of v = 8.1 m/

valina [46]

Answer:

1. α = 67.28 rad/s²

2. a = -3.04 m/s²

3. t = 0.76 s

4. x = 5.28 m

5. vf = 5.78 m/s

Explanation:

1. Let's use the torque definition: τ = Iα.

The inertial moment of a sphere is I = (2/5)*m*R²

And we know that the torque is the cross product between force and distance, so we would have τ = FxR=|F|*|R|*sin(90)=|F|*|R|=μ*mg*R

Using these two definitions, we have: (2/5)*m*R²*α = μ*mg*R

So the magnitude of the angular acceleration would be: α = (5/2R)*μ*g = 67.28 rad/s².

2. The force definition is F = m*a, when a is the linear acceleration.

F = -μ*mg.

Then -μ*mg = m*a. Solving the equation for a we have: a = -μ*g = -3.04 m/s².

3. To get the time when the ball star to rolling we need to use angular and linear velocity equation.

- ωf = ω0 + α*t ; we assume that initial angular velocity is 0.

- vf = v0 - a*t; v0 is the initial linear velocity

The relation to pure rolling is: v = ω*R. Rewriting this equation in terms of time v0 - a*t = α*t*R, so t = v0/(α*R+a) = 0.76 s.

4. Using the distance equation: xf = x0 + v0*t - 0.5*a*t² = 5.28 m.

5. vf = v0 - a*t = 5.78 m/s.

Have a nice day!

8 0

3 years ago

A proton moves with a speed of 4.00 106 m/s horizontally, at a right angle to a magnetic field. What magnetic field strength is

Free_Kalibri [48]

Answer:

Magnetic field, $B=2.55\times 10^{-14}\ T$

Explanation:

It is given that,

Speed of proton, $v=4\times 10^6\ m/s$

Mass of the proton, $m=1.67\times 10^{-27}\ kg$

Charge on proton, $q=1.6\times 10^{-19}\ C$

We need to find the magnetic field strength required to just balance the weight of the proton and keep it moving horizontally.

The Lorentz force is given by :

$F=q(v\times B)=qvB\ sin90$ .............(1)

The weight of proton,

$W=mg$ ..............(2)

From equation (1) and (2), we get :

$mg=qvB$

$B=\dfrac{mg}{qv}$

$B=\dfrac{1.67\times 10^{-27}\ kg\times 9.8\ m/s^2}{1.6\times 10^{-19}\ C\times 4\times 10^6\ m/s}$

$B=2.55\times 10^{-14}\ T$

Hence, this is the required solution.

3 0

2 years ago

anteaters are animals with long tongues that they used to wear a ant they sometimes free by poking their tongues into a bed and

True [87]

Answer: an ant eater who can’t eat

Explanation:

6 0

3 years ago

what if boy A and boy B pull the heavy cabinet at the same time in opposite directions with 10 N and 5 N of force respectedly, t

Tpy6a [65]

Answer:

side a

Explanation:

due to more force

8 0

2 years ago

Read 2 more answers