1st day: 7 bushes. Every next day Omar was clearing 3 more than he did day before.
2nd day:10 bushes
3rd day:3 more bushes than 2nd day so 6 more bushes. 10+6=16 bushes
4th day: 3 more bushes than 3rd day so 9 more bushes. 16+9=25 bushes
5th day: 9+3=12. 25+12=37 bushes.
6th day: 12+3=15. 37+15=52 bushes.
7th day: 15+3=18. 52+18=70 bushes
8th day: 18+3=21. 70+21=91 bushes cleared till 8th day.
9th day: 21+3=24. 91+24=115 bushes.
10th day: 24+3=27. 115+27=142
Omar needed 10 days to clear 140 bushes.
Answer:
Heyy
Step-by-step explanation:
△ABC is a right angled triangle and right angle at B
sinA=
AC
BC
, cosA=
AC
AB
⟹sinA+cosA=
AC
BC
+
AC
AB
=
AC
BC+AB
[We know that sum of two sides of a triangle is greater than the third side]
⟹sinA+cosA>
AC
AC
=1
Hence, sinA+cosA>1
Answer:
Step-by-step explanation:
Patterns in Multiplication 75 ... 13. 1 __. 5 of 60 = 11. 1 __. 9 of 81 = 14. 1 __. 8. ⋅ 16 = 3. 10. 7. 9. 8. 12. 2. 10. 5 ... zeros in the product for the expression 600 ⋅ 500. 4-2. 1. 5__. 8. 5__. 7. 4. ... 15. 5,000. ×. 2. __. 18. 600. ×. 4. __. 7. 5__. 6. ⋅ 36 = 10. 2 __. 3. ⋅ 33 = 8. ... Solve the first problem with Place Value Sections.