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3 years ago

Question 10 please :(

Mathematics

2 answers:

Maru [420]3 years ago

7 0

M=9.25-(4.5+3.5)
m=1.25

dezoksy [38]3 years ago

6 0

4.5 + 3.5 = 4 + 3 + 1 = 8
Janet has 1.25 remaining in her savings.

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Find the following sums. Please help.

34kurt

Answer:

5m-n-4p

4a^2+6x-3

Step-by-step explanation:

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

Combine like terms

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

(3-5+7)m +(-4+9-6)n +(7-6-5)p

5m-n-4p

a^2 -3x +1

a^2 +9x -6

2a^2 +0x +2

----------------------

Combine like terms

a^2 -3x +1

a^2 +9x -6

2a^2 +0x +2

----------------------

(1+1+2)a^2 +(-3+9+0)x +(1-6+2)

4a^2+6x-3

6 0

2 years ago

Solve............... the system

nadezda [96]

5y=-25,
y=-5
correct answer (1,-5)

7 0

3 years ago

Read 2 more answers

Adam is building a rectanglar swimming pool. The perimeter of the pool must be no more then 120 feet. If the length of the pool

jasenka [17]

Answer:

$W\leq 38\ ft$

The maximum width must be $38\ ft$

Step-by-step explanation:

Let

L ----> the length of the rectangular pool

W ---> The width of the rectangular pool

we know that

$P\leq 120\ ft$

$P=2(L+W)$

$2(W+L)\leq 120$ ----> inequality A

we have

$L=22\ ft$

substitute the value of L in the inequality A

$2(W+22)\leq 120$

simplify

$(W+22)\leq 60$

$W\leq 60-22$

$W\leq 38\ ft$

The maximum width must be $38\ ft$

3 0

3 years ago

Use law of sines or law of cosines to find the length of side AB Please show work !!

scoray [572]

Answer:

$AB = 11.3$

Step-by-step explanation:

Given

The attached triangle

Required

Length AB

To do this, we make use of sine law which is represented as:

$\frac{a}{\sin(a)} = \frac{b}{\sin(b)} = \frac{c}{\sin(c)}$

So, we have:

$\frac{15}{\sin(70)} = \frac{AB}{\sin(45)}$

Make AB the subject

$AB = \frac{15}{\sin(70)} * \sin(45)$

$AB = \frac{15}{0.9397} *0.7071$

$AB = 11.3$

7 0

3 years ago

122. Write the equation of the line that is

Marina CMI [18]

When a line is given in the form

$y=mx+q$

The slope of the line is m. So, in this case, the slope of $y=x-5$ is 1.

Given a slope $m$ , you find the slope of a perpendicular line $m'$ by imposing

$m\cdot m' = -1$

So, if the given line has slope 1, a perpendicular line has slope $m'$ given by

$1 \cdot m' = -1$

and thus $m'=-1$

So, we want a line with slope -1 and passing through (12,-1). Using the fomula

$y-y_0=m(x-x_0)$

we get

$y-(-1)=-1(x-12) \iff y+1=-x+12 \iff y=-x+11$

5 0

3 years ago