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poizon [28]
3 years ago
13

Write an equation in slope-intercept form for the line perpendicular to y = -4x + 2 that passes through the point (–5, 2).​

Mathematics
1 answer:
cricket20 [7]3 years ago
6 0

Answer:

y = 5 /2 x − 2

Step-by-step explanation:

The slope-intercept form of a linear equation is:  y = m x + b   Where  m  is the slope and  b  is the y-intercept value.

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Quick question! Will give brainliest!
Sever21 [200]

Answer:

3

3 rectangles have vertices ABCD that lie on grid nodes

Step-by-step explanation:

3 0
2 years ago
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Please help me I'm stuck on this one
Colt1911 [192]
Ok i should know this i had the same test sum goes to 0 5/8 goes to 5/8 and m goes to -5/8 

hope this helps!
6 0
3 years ago
Which products result in a perfect square trinomial? Check all that apply.
sladkih [1.3K]

The <em><u>correct answers</u></em> are:

B=(xy + x)(xy + x) ; C=(2x – 3)(–3 + 2x) ; and E=(4y² + 25)(25 + 4y²)

Explanation:

In order to have a perfect square trinomial, we must multiply two binomials that are exactly the same.  For (xy+x)(xy+x), are multiplying two identical binomials.

For (2x-3)(-3+2x), we are multiplying two binomials that are the same but written in a different order.  The same is true of (4y² + 25)(25 + 4y²).

3 0
3 years ago
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Please answer this question
Ann [662]
9.9=9×9=81 and you have to multiply
6 0
3 years ago
What is 9/10 + 7/15
Yakvenalex [24]

\huge\text{Hey there!}

\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}

\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}

\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}

\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}

\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}

\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}

\mathsf{= \dfrac{27+14}{30}}

\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}

\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}

\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

6 0
2 years ago
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