Answer:
f(x)=(x+1)^2-2 is the minimum and g(x)=-(x-2)^2+1 is the maximum
Step-by-step explanation:
Looking at the graph, (you should be able to graph this) the parabola for f(x)=(x+1)^2-2 is pointing downwards and stops at the vertex. This vertex is negative which is the lowest point possible which makes it the minimum. The parabola for -(x-2)^2+1 is pointing upwards and stops at the vertex which is the highest point possible which makes it the maximum.
Answer:
B
Step-by-step explanation:
Firstly, we solve for x
-x ≥ 2 * 4
-x ≥ 8
Multiply both sides by -1
x ≤ -8
So we look at the inequality represented by this;
We can see that the correct inequality is option B;
The first step to solving an equation like this is to find the slope of a line that will be perpendicular to the line given. The slope of a line that's perpendicular to another line is the negative reciprocal. The negative reciprocal of -1/5 is 5. So, so far our equation is y = 5x + b. Now, to find what b is equal to, we should substitute the values of x and y from the point (1,2) since we know that our line goes through the point. Our equation becomes:
2 = 5 + b
b= -3
That means that the equation of our new line is y = 5x - 3
Answer = 2x^2+6x+1
3x+2+2x^2+3x-1
3x+1+2x^2+3x
Now combine like terms
3x+1+2x^2+3x
6x+1+2x^2
Rearrange terms
6x+1+2x^2
2x^2+6x+1
