3 years ago

Write an equation in slope-intercept form for the line perpendicular to y = -4x + 2 that passes through the point (–5, 2).

Mathematics

1 answer:

cricket20 [7]3 years ago

6 0

Answer:

y = 5 /2 x − 2

Step-by-step explanation:

The slope-intercept form of a linear equation is: y = m x + b Where m is the slope and b is the y-intercept value.

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Eva8 [605]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

How do you find the equation for the line that is parallel to the line y=2/3x-7 and passes through the point (3,-1)

Debora [2.8K]

parallel lines have the same exact slope hmmm what's the slope of y = 2/3x-7 anyway? well, low and behold, is already in slope-intercept form, therefore

$\bf \stackrel{\textit{slope-intercept form}}{y=\stackrel{slope}{\cfrac{2}{3}}x-7}$ .

so we're really looking for the equation of a line whose slope is 2/3, and runs through 3, -1.

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-1})~\hspace{7em} slope = m\implies \cfrac{2}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=\cfrac{2}{3}(x-3) \\\\\\ y+1=\cfrac{2}{3}x-2\implies y=\cfrac{2}{3}x-3$

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3 years ago

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Gala2k [10]

Answer:

Step-by-step explanation:

926/71 = 13 Remainder 3

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3 years ago

Write an equation in slope-intercept form for the line perpendicular to y = -4x + 2 that passes through the point (–5, 2).​

Write an equation in slope-intercept form for the line perpendicular to y = -4x + 2 that passes through the point (–5, 2).