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Sindrei [870]
3 years ago
13

Which expression is the factorization of x2 + 10x + 21? (x + 3)(x + 7) (x + 4)(x + 6) (x + 6)(x + 15) (x + 7)(x + 14)

Mathematics
2 answers:
vitfil [10]3 years ago
8 0

Answer:

A: (x + 3)(x + 7)

Step-by-step explanation:

Vadim26 [7]3 years ago
5 0

Answer: First option.

Step-by-step explanation:

You need to remember that to factorize the given expression x^2+10x+21, you need to choose two numbers that when you add them you get "10" and when you multiply them you get "21".

These number are:

7 and 3

Because:

7+3=10\\7*3=21

Therefore, you get that the factorization of the expression x^2+10x+21 is the following:

(x+3)(x+7)

You can observe that this factorization matches with the first option.

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Harman [31]
The answer is the top left.
Since it is a > sign, it will be a dotted line and a shade to the right (greater). As for x, it is greater than 2. Thus, the graph will be a dotted line connecting the points of which the x coordinate is 2,and shaded to the right.
7 0
3 years ago
Plss I need this quickly I don't understand this<br>3(x-6)=6+7​
Rufina [12.5K]

Answer:

x = \frac{31}{3}

Step-by-step explanation:

Given

3(x - 6) = 6 + 7, that is

3(x - 6) = 13 ← distribute parenthesis on the left side by 3

3x - 18 = 13 ( add 18 to both sides )

3x = 31 ( divide both sides by 3 )

x = \frac{31}{3}

6 0
3 years ago
Un curso esta formado por 12 mujeres y 15 hombres ¿cual es la probabilidad de que las personas en el cargo de presidente y visep
riadik2000 [5.3K]

Answer:

P = (12/27)*(11/26) = 0.188

Step-by-step explanation:

Si todos tienen la misma probabilidad de estar en cargo de presidente y vicepresidente, entonces:

La probabilidad de que una mujer sea presidente, es igual al cociente entre el número de mujeres y el número total de personas:

p = 12/27

Ahora queremos calcular lo mismo para vicepresidente, y el cálculo es exactamente igual, con la diferencia de que en esta situación, ya hay una mujer en el cargo de presidente, entonces hay 11 mujeres que pueden ser vicepresidente, y un total de: (11 + 15 = 26 personas)

Entonces ahora la probabilidad es:

q = 11/26

La probabilidad conjunta (es decir, la probabilidad de que ambos eventos pasen) es igual al producto de las probabilidades individuales.

P = (12/27)*(11/26) = 0.188

4 0
2 years ago
Please Help Me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
GuDViN [60]

Answer:

(-2, 11) and (2, 3)

Step-by-step explanation:

<u>Given system of equations:</u>

1) f(x) = x² - 2x + 3 ⇒ y = x² - 2x + 3

2) f(x) = -2x + 7 ⇒ y = -2x + 7

Solve Using the Substitution Method:

<u>Step 1:</u> Substitute the the first equation into the second.

⇒ x² - 2x + 3 = -2x + 7

<u>Step 2:</u> Solve for x.

x² - 2x + 3 = -2x + 7 [ Add 2x to both sides. ]

x² - 2x + 2x + 3 = -2x + 2x + 7

⇒ x² + 3 = 7 [ Subtract 3 from both sides. ]

x² + 3 - 3 = 7 - 3

⇒ x² = 4 [ Take the square root of both sides. ]

√x² = √4

x = ± 2

⇒ x = -2, x = 2

<u>Step 3:</u> Solve for y.

<em>Substitute the found x-values into one of the given equations.</em>

y = -2x + 7 ⇒ y = -2(-2) + 7 ⇒ y = 4 + 7 ⇒ y = 11

y = -2x + 7 ⇒ y = -2(2) + 7 ⇒ y = -4 + 7 ⇒ y = 3

The solutions to the system of equations are: (-2, 11) and (2, 3).

Learn more about system of equations here:

brainly.com/question/26094713

brainly.com/question/27850666

5 0
2 years ago
Read 2 more answers
Assume that all six outcomes of a six-sided number cube have the same probability. What is the theoretical probability of each r
Margarita [4]
Hey there! I am on the same one. :) I will help you out a little. 

<span>Assume that all six outcomes of a six-sided number cube have the same probability. What is the theoretical probability of each roll? 
• 1: 1/6
• 2: 2/6
• 3: 3/6
• 4: 4/6
• 5: 5/6
• 6: 6/6
</span>
<span>Using the uniform probability model you developed, what is the probability of rolling an even number? 
1/6 Roll a number cube 25 times. Record your results here. 

</span><span> <span><span> <span> <span>1st toss=</span>6</span> </span> <span> <span> <span>2nd toss=</span>4</span> </span> <span> <span> <span>3rd toss=</span>6</span> </span> <span> <span> <span>4th toss=</span>6</span> </span> <span> <span> <span>5th toss=</span>3</span> </span> <span> <span> <span>6th toss=</span>3</span> </span> <span> <span> <span>7th toss=</span>4</span> </span> <span> <span> <span>8th toss=</span>2</span> </span> <span> <span> <span>9th toss=</span>6</span> </span> <span> <span> <span>10th toss=</span>5</span> </span> <span> <span> <span>11th toss=</span>1</span> </span> <span> <span> <span>12th toss=</span>4</span> </span> <span> <span> <span>13th toss = </span>5</span> </span> <span> <span> <span>14th toss =</span>1</span> </span> <span> <span> <span>15th toss=</span>4</span> </span> <span> <span> <span>16th toss=</span>2</span> </span> <span> <span> <span>17th toss=</span>2</span> </span> <span> <span> <span>18th toss=</span>2</span> </span> <span> <span> <span>19th toss=</span>6</span> </span> <span> <span> <span>20th toss=</span>5</span> </span> <span> <span> <span>21st toss=</span>3</span> </span> <span> <span> <span>22nd toss=</span>4</span> </span> <span> <span> <span>23rd toss=</span>3</span> </span> <span> <span> <span>24th toss=</span>3</span> </span> <span> <span> 25 toss=5
How many results of 1 did you have? __2____________ How many results of 2 did you have? ____4__________ How many results of 3 did you have? ____5__________ How many results of 4 did you have? ______5________ How many results of 5 did you have? ______4________  How many results of 6 did you have? ______5________
Based on your data, what is the experimental probability of each roll?  <span> 1. 2/25 or 0.08 

2. 4/25 or 0.16

3. 5/25 or 0.24

4. 5/25 or 0.2

5.4/25 or 0.16
<span>
6. 5/25 or 0.2</span></span>Using the probability model based on observed frequencies, what is the probability of rolling an even number? 3/6 = ½ or 0.5
Was your experimental probability different than your theoretical probability? Why or why not? <span>It somewhat is! The denominator is 25 for the experimental probability, and 6 for the theoretical probability.</span><span>
</span><span>Have a lovely day! Cheerio. :) </span></span> </span> </span></span>
8 0
3 years ago
Read 2 more answers
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