It is more than just a quadrilateral. In fact it is going to be hard to pick.
These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.
The converse is "If you have a parallelagram, the diagonals bisect each other."
You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.
2 years late. Here is the answer for people in the future. It is D. g(x)=x-6
2 feet I think, I could be wrong
Answer:
7) B, C
8) D
Step-by-Step-Explanation:
The first thing you need to solve for is the the parenthesis
the second one simplifies to x ≤ -7
Answer:
Step-by-step explanation:
The first box should be 20.
The second box should be 40
The third box should be .2
The fourth box should be .6
