13 143rds would be written as 13/143.
For the top angles you would solve them by setting them equal to each other, so you would do 3x+5=17x-70. You can then add 70 to both sides, getting 3x+75=17x. You can then subtract 3x from both sides, getting 75=14x. You then divide both sides, getting 5 5/14 or around 5.36 as x. You can then add plug that into 3x+5, getting around 21.07. You can then make the equation R=180-21.07. You'd get 158.93.
Answer:
Given the expression: 
Let the value of the given expression in radians be 
then;
......[1]
We know the value of 
Substitute the given value in [1] we have;
Since, the value of 
is 0, therefore, the value of is in the form of:
; where n is the integer.
At n =0, 1 and 2, {Since, n is the integer}
Value of 
and 
therefore, the answer in radians either 
or
Answer:
(A) 0.0244
(B) 1 (not 1.47 as is calculated) since probability values are between 0 and 1; 0 and 1 inclusive
Step-by-step explanation:
The rare mutation only occurs in 1 generation, out of every 2048 generations. This implies that the next occurrence will fall in or within the next 2048 generations (2 generations in 4096 generations, will have the rare mutation).
(A) The probability of occurrence of this mutation at least once (at most infinity) in 50 generations of fruit flies will surely be less than, as 50 is less than 2048.
The accurate probability is gotten when 50 is divided by 2048
50÷2048 = 0.0244
(B) The probability of seeing this mutation at least once (at most infinity) in 3000 generations would have been 1.47 but for 3 reasons;
- The full question already tells that the mutation will occur once in every 2048 generations and 3000 is greater than 2048, hence there will be a sure occurrence within 3000 generations.
- Question (b) asks you to calculate the probability of seeing this mutation at least once in 3000 generations so, the probability is 1 (representing full probability).
- In probability theory or statistics, all probability values fall within 0 and 1; with 0 representing no occurrence at all and 1 representing full occurrence.
It’s A 44-1) and if not then it’s b
