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Lera25 [3.4K]
3 years ago
14

The coefficient of x^ky^n-k in the expansion of (x+y)^n equals (nk). True or false.

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

The correct option is;

False

Step-by-step explanation:

The coefficient of x^k·y^(n-k) is nk,   False

The kth coefficient of the binomial expansion, (x + y)ⁿ is  \dbinom{n}{k} = \dfrac{n!}{k!\cdot (n-k)!} = C(n,k)

Where;

k = r - 1

r = The term in the series

For an example the expansion of (x + y)⁵, we have;

(x + y)⁵ = x⁵ + 5·x⁴·y + 10·x³·y² + 10·x²·y³ + 5·x·y⁴ + y⁵

The third term, (k = 3) coefficient is 10 while n×k = 3×5 = 15

Therefore, the coefficient of x^k·y^(n-k) for the expansion  (x + y)ⁿ = C(n,k) not nk

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Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, what perce
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At the end of three days,  72.9% of the original amount of liquid remains in Kyle's container .

<u>Step-by-step explanation:</u>

Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:

Let's suppose initially we have 100% of liquid present so ,

<u>At day 1:</u>

10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :

⇒ 100- \frac{100(10)}{100}

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<u>At day 2:</u>

10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :

⇒ 90- \frac{90(10)}{100}

⇒ 90-9

⇒ 81%

<u>At day 3:</u>

10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :

⇒ 81- \frac{81(10)}{100}

⇒ 81-8.1

⇒ 72.9%

Therefore , At the end of three days,  72.9% of the original amount of liquid remains in Kyle's container .

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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jeff wants to buy a phone card for long distance calls. he can buy a 200-minute card for $10.00 or a 300-minute card for $12.00.
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3 years ago
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