All categories

3 years ago

Suppose Đ1 and Đ2 are known to be complementary. If mÐ1 = 20, then mÐ2 =

Mathematics

1 answer:

juin [17]3 years ago

6 0

Answer:

Step-by-step explanation:

complementary angles are 2 angles that add up to 90, the first angle is already 20 so just subtract 90-20 to find other angle

You might be interested in

Suppose a company claims that its jars of pickles weigh 68 ounces on average. It took many large samples, and about half the tim

Annette [7]

Step-by-step explanation:

The company's jars of pickles weigh fewer than 68 ounces on average. C. The company's jars of pickles weigh more than 68 ounces on average. D. The company's jars of pickles do not weigh 68 ounces on average.

This is the Answer

4 0

3 years ago

Find the simple interest for : $668,5%, 2 years

Mkey [24]

Answer: 2 years

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A polygon has the vertices P(-2,6), Q(4,6), R(4,1) and S(-2,1). What is the length of side RS?

inessss [21]

It is 6 units because you find the absolute value of the two different coordinates, in this case it is 4 and -2. Since they belong in different quadrants (one x or y value is positive and the other is negative) you add them. If they are both in the same quadrant, you subtract them.

8 0

3 years ago

Find the missing side length Plsss help

ElenaW [278]

Answer:

I would be 21 for the missing side

3 0

3 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

Read 2 more answers