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nikklg [1K]
3 years ago
8

67+46 Find the solution and model how you found your answer

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

113

Step-by-step explanation:

7 plus 6 is 14 carry the one over to the 6 of the 67 then add the one the six and the four that equals 11

that gets you

113

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Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Alisiya [41]
This will be a 4th degree polynomial.  Our root of x = 7 in factorization form is (x-7).  Our root of x = -11 in factorization form is (x+11) and the last one is a complex number.  According to the conjugate root theorem, if we have 2+8i, we also HAVE to have 2-8i.  In factorization form that first one is (x-(2+8i)) which simplifies to (x-2-8i).  Its conjugate in factorization form is (x-2+8i).  Now we will FOIL all that out.  Let's start with the (x-2-8i)(x-2+8i).  That multiplies out to x^2-2x+8ix-2x+4-16i-8ix+16i-64i^2.  We have to combine like terms here to shorten that a bit.   x^2-4x+4-64i^2.  i^2 is equal to -1, and -1(64) = -64.  Now we have  x^2-4x+4-(-64).  That is  x^2-4x+68.  Now let's FOIL in another factorization.  (x^2-4x+68)(x-7).  That comes out to  x^3-11x^2+96x-476.  One more term to go!  x^3-11x^2+96x-476)(x+11).  That, finally, is x^4-25x^2+580x-5236. 
5 0
3 years ago
On 31 August 2018,Musk Traders purchased a machine on credit for a cost price of R402 500(including VAt at 15%). Machinery is de
mariarad [96]

Answer:

Depreciation should be on a value net of VAT.

Cost + (Cost * VAT) = 402,500

Cost + Cost * 15% = 402,500

1.15 * Cost = 402,500

Cost = $350,000

Depreciation is straight line for 6 years so per year is = 350,000/6 = $58,333

2019

In 2019 the June year end from date of purchase will be 10 months.

Depreciation in 2019

= Yearly depreciation * 10/12 months

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= $48,611

Accumulated Depreciation 2019

= $48,611

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2020 will be a complete year so depreciation

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Accumulated Depreciation 2020

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= 48,611 + 58,333

= $‭106,944‬

4 0
3 years ago
7. If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is?​
prisoha [69]

<em><u>(0.2)x = 2.</u></em>

<em><u>Taking log on both sides</u></em>

<em><u>log (0.2)x = log 2.</u></em>

<em><u>x</u></em><em><u> </u></em><em><u>log (0.2) = 0.3010, [since log 2 = 0.3010].</u></em>

<em><u>x</u></em><em><u> </u></em><em><u>log (2/10) = 0.3010.</u></em>

<em><u>x</u></em><em><u> </u></em><em><u>[log 2 - log 10] = 0.3010.</u></em>

<em><u>x</u></em><em><u> </u></em><em><u>[log 2 - 1] = 0.3010,[since log 10=1].</u></em>

<em><u>x[-0.699] = 0.3010.</u></em>

<em><u>x</u></em><em><u>=</u></em><em><u> </u></em><em><u>0.3010/-0.699.</u></em>

<em><u>x</u></em><em><u>=</u></em><em><u> </u></em><em><u>= -0.4306….</u></em>

<em><u>x</u></em><em><u>=</u></em><em><u> </u></em><em><u>= -0.4</u></em><em><u>.</u></em>

7 0
2 years ago
Read 2 more answers
To assess the learning outcomes of a Statistic course, 5 students are chosen at random from each of the 30 Statistics classes an
zhannawk [14.2K]

Answer: simple random sampling

Step-by-step explanation:

In statistics, when a subset of individuals known as sample chosen from a population by a random selection of individuals such that the chances of selecting each individual is same, then the sampling method is called simple random sampling method.

Given: To assess the learning outcomes of a Statistic course, 5 students are chosen at random from each of the 30 Statistics classes.

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3 years ago
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KATRIN_1 [288]

Answer:

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Step-by-step explanation:

in this equation, y represents wages and x represents number of copies sold

lets take the trendline, y=6x+120

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570=6x+120

450=6x

x=75

1) 75 copies r sold

2) this time we substitue the 100 for x

y=6(100)+120

y=600+120

y=720

2) expected wage=720

4 0
3 years ago
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