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Ilya [14]
3 years ago
10

If 2 sq rt 2x = 2 sq rt 3, what is the value of x?

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

<u>The correct answer is x = 3/2</u>

Step-by-step explanation:

2 √2x = 2√3, what is the value of x?

Let's solve for x, this way:

2 √2x = 2√3

√2x = √3 (Dividing by 2 at both sides)

(√2x) ² = (√3) ²  (Raising both sides at the 2nd power)

2x = 3

x = 3/2 (Dividing by 2 at both sides)

<u>The correct answer is x = 3/2</u>

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#1: Write the equation of the graphed line. NO SPACES, ALL LOWERCASE. <br> Please help
ivanzaharov [21]

Answer:

Equation of graphed line is \mathbf{y=\frac{2}{3}x-3}

Step-by-step explanation:

We need to write the equation of the graphed line.

The equation will be in slope intercept form y=mx+b where m is slope and b is y-intercept

We need to find slope and y-intercept.

Finding slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We will use points (0,-3) and (3,2)

Looking at the graph, we get x_1=0, y_1=-3, x_2=3, y_2=-1

Putting values in graph and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-1-(-3)}{3-0}  \\Slope=\frac{-1+3}{3}  \\Slope=\frac{2}{3}

So, we get slope \mathbf{\frac{2}{3}  }

Finding y-intercept

y-intercept can be found when x is zero.

So, looking at graph, when x =0, y=-3

So, y-intercept is -3

Equation of Line

So, equation of line having slope \mathbf{\frac{2}{3}  } and y-intercept b = -3

y=mx+b\\y=\frac{2}{3}x-3

So, Equation of graphed line is \mathbf{y=\frac{2}{3}x-3}

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