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k0ka [10]
3 years ago
11

Can you help me with this please

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0
What do you need help with
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Find the equation of the line that passes through the points (12,21) and (46,33). V.35r-162
AnnZ [28]

Answer:

the answer is Y=(6/17)X + (285/17)

Step-by-step explanation:

1. Identify the X and Y coordinate of each point.            

for example, the first point could be (12,21), therefore X1 = 12 and Y1 = 21 and the second point is then (46,33), therefore X2 = 46 and Y2 = 33

2. to find the equation of the line it is necessary to find the slope.

knowing that the equiation of the slope is M = Y2-Y1/X2-X1 we replace

  m=\frac{33-21}{46-12}=\frac{12}{34} and then we simplify the result to \frac{12}{34}

3. Using the Point-slope equation which is  Y-Y1=M(X-X1) we replace

 Y-33=\frac{6}{17}(X-46)

Y=\frac{6}{17}X-\frac{276}{17}+33

Y=\frac{6}{17}X+\frac{285}{17}

7 0
3 years ago
A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What
GalinKa [24]

Answer:

(1) The slope of the line segment AB is 1.\bar 3

(2) The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is (5, 7)

(4) The slope of a line perpendicular to the line AB is-0.75

Step-by-step explanation:

The coordinates of the line segment AB are;

A(2, 3) and B(8, 11)

(1) The slope of a line segment is given by the following equation;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where;

(x₁, y₁) and (x₂, y₂) are two points on the line segment

Therefore;

The slope, m, of the line segment AB is given as follows;

A(2, 3) = (x₁, y₁) and B(8, 11) = (x₂, y₂)

Slope, \, m_{AB} =\dfrac{11-3}{8-2} = \dfrac{8}{6}  = 1 \frac{1}{3} = 1.\bar3

The slope of the line segment AB = 1.\bar 3

(2) The length, l, of the line segment AB is given by the following equation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Therefore, we have;

l_{AB} = \sqrt{\left (11-3  \right )^{2}+\left (8-2  \right )^{2}} = \sqrt{64 +36} = 10

The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is given as follows;

Midpoint, M = \left (\dfrac{x_1 + x_2}{2} , \ \dfrac{y_1 + y_2}{2} \right )

Therefore;

Midpoint, M_{AB} = \left (\dfrac{2 + 8}{2} , \ \dfrac{3 + 11}{2} \right ) = (5, \ 7)

The coordinates of the midpoint of AB is (5, 7)

(4) The relationship between the slope, m₁, of a line AB perpendicular to another line DE with slope m₂, is given as follows;

m_1 = -\dfrac{1}{m_2}

Therefore, the slope, m₁, of the line perpendicular to the line AB, that has a slope m₂ = 4/3 = 1.\bar 3 is given as follows;

m_1 = -\left (\dfrac{1}{\frac{4}{3} } \right ) = -\dfrac{3}{4}  = -0.75

The slope, m₁, of the line perpendicular to the line AB is m₁ = -0.75.

8 0
3 years ago
Josiah went to the local barber to get his haircut. It cost $18 for the haircut. Josiah tipped the barber 15%. What was the tota
salantis [7]

Answer:

2.70

Step-by-step explanation:

5 0
3 years ago
Jane drove 360 miles in 5 hours. At the same rate,how many miles would she drive in 13 hours
VLD [36.1K]

Answer:

936

Step-by-step explanation:

360 divided by 5 = 72

72 x 13 = 936

8 0
3 years ago
Read 2 more answers
Find the distance between the points (0, –3) and (4, 0).
V125BC [204]

Answer:

5 units

Step-by-step explanation:

Distance = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}

d = \sqrt{(0 - 4)^2 + (-3 - 0)^2}

d = \sqrt{(-4)^2 + (-3)^2}

d = \sqrt{16 + 9}

d = \sqrt{25}

d = 5

So, the distance between the points is 5 units which is letter choice B.

7 0
3 years ago
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