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3 years ago

Which tables represent constant functions?

Mathematics

2 answers:

Softa [21]3 years ago

7 0

Answer:

The correct option is C and E.

Step-by-step explanation:

Constant functions is the function those output value(y) remains same for any input values(x).

Now consider the provided options.

Option A, B and D has different output value(y) for different the different input values(x)

Now consider the option C and E.

Option C and E has same output value(y) for different the different input values(x).

Therefore, the correct option is C and E.

musickatia [10]3 years ago

6 0

Answer:

C and E repr. constant functions.

Step-by-step explanation:

C and E represent constant functions. One can tell immediately by the fact that y remains the same even when x changes.

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Subtract. Express your answer in lowest terms. 10 5/11 - 4 2/11

Zigmanuir [339]

Answer:

6 3 /11

Step-by-step explanation:

10 5/11 - 4 2/11

since they already have a common denominator

10 5/ 11

- 4 2 /11

-------------

6 3 /11

6 0

3 years ago

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How many ways can nick choose 5 pizza toppings from a menu of 11 toppings

Stells [14]

Answer:

462

Step-by-step explanation:

Using choosing, we can choose 5 pizza topping out of 11. 11!/5!/(11-5)! = 462.

Can I have Brainiest if I'm correct?

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3 years ago

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Pastries made out of filo dough and brushed with either olive oil or butter (but not both). Pastries made out of shortcrust doug

Genrish500 [490]

Answer:

$\frac{9x}{40}$ is the answer.

Step-by-step explanation:

The question has some typo errors.

Rashid and Mikhail submitted a total of x pastries to a baking competition.

Suppose say :

Mikhail made x pastries .

Hence Rashid made $\frac{2x}{3}$ pastries.

And in total they made $\frac{5x}{3}$ pastries.

Now we have that out of x, $\frac{5}{8}$ of x were brushed with olive oil.

So, $\frac{3}{8}$ of x that is $\frac{3x}{8}$ are brushed by butter.

So, it becomes $(\frac{3}{8}) / ( \frac{5x}{3} )$

= $\frac{3}{8} \times\frac{3x}{5}$ = $\frac{9x}{40}$

Hence, answer is option B.

6 0

3 years ago

-3 + 9 ( 102 - 4 ) (simplify)

daser333 [38]

Answer: 879

Step-by-step explanation:

The order of operations calls for Parenthesis, Multiply, Divide, Add, Subtract. From left to right.

So we do the parenthesis first (102 - 4)

-3 + 9 (98)

Next we multiply 9 and 98

-3 + 882

Lastly we add -3 and 882

879

4 0

3 years ago

How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$

b) In this case we need to solve a first order ordinary differential equation of the following form:

$\frac{dy}{dx} + p(x) \cdot y = q(x)$ (2)

Where:

$p(x)$ - Integrating factor
$q(x)$ - Particular function

Hence, the ordinary differential equation is equivalent to this form:

$\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x}$ (3)

The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ . $\blacksquare$

The solution for (2) is presented below:

$y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C$ (4)

Where $C$ is the integration constant.

If we know that $p(x) = -\frac{1}{x}$ and $q(x) = x^{2} + \frac{1}{x}$ , then the solution of the ordinary differential equation is:

$y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C$

$y = x\int {x} \, dx + x\int\, dx + C$

$y = \frac{x^{3}}{2}+x^{2}+C$

If we know that $x = 1$ and $y = -1$ , then the particular solution is:

$y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ . $\blacksquare$

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0

3 years ago