Answer:
i think im late
Step-by-step explanation:
General exponential equation
y = A(1+r)^x
where
A = initial value
r = rate increase (+) or decrease (-)
x = time period of the change
y = projected value
y = 300(1.05)^x
in this problem, x = years after 2017
we want to find an x that makes the value more than or equal to 650
650 <= 300(1.05)^x
Answer:
5
Step-by-step explanation:
Answer:
I believe the answer is B
