There are 2 tangent lines that pass through the point

and

Explanation:
Given:

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:
![[1]](https://tex.z-dn.net/?f=%5B1%5D)
For the lines to be tangent to the curve, we must substitute the first derivative of the curve for
:



![[2]](https://tex.z-dn.net/?f=%5B2%5D)
Substitute equation [2] into equation [1]:
![[1.1]](https://tex.z-dn.net/?f=%5B1.1%5D)
Because the line must touch the curve, we may substitute 

Solve for x:




± 
±
<em> </em>

There are 2 tangent lines.

and

Answer: -83
Step-by-step explanation:
f(9)--22+20-9*(9)=-2-81=-83
Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
Answer:
The value of x = 3.42
Step-by-step explanation:
Formula:
Sin ∅ = Opposite side /Hypotenuse
From the figure we can see a right angled triangle.
One angle is given, hypotenuse = 10 and height = x.
To find the value of x
sin 20 = Opposite side/hypotenuse = x/10
x = 10 * sin 20
= 10 * 0.342 = 3.42
Therefore the value of x = 3.42
Answer:
The indefinite integral
=
ˣ
⁺ C
Step-by-step explanation:
x= 10sinθ
dx = 10cosθdθ
the step-to-step explanation is in the attachment