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Valentin [98]
3 years ago
13

If x=√3+√2, then the value of x3−1x3 is equal to21√242√222√221√3​

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0

Answer:

hello.. please follow me first if you want me to answer your question.

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Which vector has a greater magnitude?
jonny [76]

Given:

Length of first vector = 2 meters

Length of second vector = 4 meters

To find:

The vector which has a greater magnitude.

Solution:

We know that, magnitude of a vector represents the length of it.

The first vector that is 2 meters long has a magnitude 2.

The second vector that is 4 meters long has a magnitude 4.

Clearly, 4 is greater that 2, i.e., 4 > 2. So, magnitude of second vector is greater.

Therefore, the vector that is 4 meters long has greater magnitude.

7 0
3 years ago
Myra bought a pair of jeans that cost $55. The sales tax rate is 10 percent. What is the total amount she paid for the jeans?
Semmy [17]
You need to calculate the sale tax and add it to the value of the pair of pants. The tax is calculated by multiplying the cost of the pants times the rate, i.e.tax = $55 * 10% = $55 * 10/100 = $ 55*0.1 = $ 5.5. Now sum this tax to the cost of the pants: $ 55 + $5.5 = $ 60.5. Then, the answer is $ 60.50
3 0
3 years ago
Solve the problem<br> Show your work<br> 16.007<br> - 0.55<br> ----------
Roman55 [17]

Answer:

16.007 - 0.55 is 15.457

5 0
3 years ago
Read 2 more answers
Evaluate the expression (ab)2 for a = 2 and b = 5.
kirill [66]

Answer:

-50

Step-by-step explanation:

First, we must know that ab is the same as:

ab is the same as a multiply b

Now, since a is given as -5, we can substitute a with -5. This is shown below:

substitute ab with -5

Similarly, b is given as 10. So, we can substitute b with 10:

substitute b with 10

With this, we can now evaluate ab as shown below:

ab is equal to -50

7 0
2 years ago
Suppose that the cost of producing n pairs of shoes is given by the expression c(n)=30+5n. the average cost of producing a pair
makkiz [27]
<h3>Given</h3>

c(n)=30+5n\\a(n)=\dfrac{c(n)}{n}

<h3>Find</h3>

\dfrac{d}{dn}(a(n))\quad\text{at n=10}

<h3>Solution</h3>

\dfrac{d}{dn}(a(n))=\dfrac{d}{dn}\left(\dfrac{30+5n}{n}\right)=\dfrac{d}{dn}\left(30n^{-1}+5\right)\\\\=-30n^{-2}\\\\=-30\cdot 10^{-2}\qquad\text{at n=10}\\\\=-0.30

The derivative of the average cost function at n=10 is -0.30.

7 0
3 years ago
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