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Law Incorporation [45]
3 years ago
10

Tangent segments from a common external point are

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Answer:

  • <em>Tangent segments from a common external point are</em> <u>congruent</u>

Explanation:

A <em>tangent</em> line to a circle is a line that touches the circle in only one point of the cirfumference, and, hence, the tangent is perpendicular to (forms a right angle with) the radius of the circle.

There are many thorems relative fo the tangent lines of a cirle.

One of those theorems states that if two tangent lines to a circle are drawn from a same external point, the two segments formed from the coomon external point to the tangency points have the same length.

Also, you must know that, from the definition, two segments of the same length are known as congruent segments.

Therefore, calling P the common external point, A one point of tangency in the circle, and B the other point of tangency, then:

  • length segment PA = length segment PB.

  • So, the two <u><em>tangent segments from an common enternal point are congruent.</em></u>
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If u={1,2,3,4,5},A={2,4} and Beta {2,5,5}find n(AUB)​
slavikrds [6]

<em>u={1,2,3,4,5},A={2,4} and Beta {2,5,5}</em>

<em>now</em><em>,</em><em> </em><em>(AUB)</em><em>=</em><em>{</em><em>1</em><em>,</em><em>3</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em>

<em>[</em><em>AUB</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>set</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>elements</em><em> </em><em>of</em><em> </em><em>set</em><em> </em><em>A</em><em> </em><em>and</em><em> </em><em>set</em><em> </em><em>B</em><em> </em><em>without </em><em>any</em><em> </em><em>repetition </em><em>]</em>

<em>n</em><em>(</em><em>AUB</em><em>)</em><em>=</em><em>5</em>

<em>n</em><em>(</em><em>AUB</em><em>)</em><em>is</em><em> </em><em>the</em><em> </em><em>total</em><em> </em><em>no</em><em> </em><em>of</em><em> </em><em>elements</em><em> </em><em>in</em><em> </em><em>set</em><em> </em><em>(</em><em>AUB</em><em>)</em>

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4 years ago
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Answer:

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3 years ago
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. The ratio of the area of circle A to the area of circle B is 12/5. What is the ratio of their circumferences?
N76 [4]

Answer:

1.5

Step-by-step explanation:

a : b = 1 : 12/5

Area of a circle = πr²

Where : = π = pi = 22/7

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Area of circle A = 1π

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circumference of circle B = 2 x n x 1.5 = 3n

ratio of circumference = 3n / 2n = 1.5

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