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4 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics

1 answer:

BabaBlast [244]4 years ago

7 0

Hey!

Weight of small box = 5 lb. x no. of small boxes total weight = 5*x

Weight of Large boxes = 12 lb. y no. of large boxes total weight = 12*y

Total weight = 5x + 12y.

Since total weight carrying capacity of shelf is 80, thus the inequality becomes:

5x + 12y Less than or equal to 80.

(a) satisfies the inequality.

(b) satisfies the inequality.

Hope my answer helps!

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B. The school prom committee sold presale tickets for

Ivan

Answer:

218 students purchased tickets at the dance.

Step-by-step explanation:

Let,

x be the number of presale tickets

y be the number of tickets sold at the dance

According to given statement;

x+y=334 Eqn 1

18x+24y=7320 Eqn 2

Multiplying Eqn 1 by 18

18(x+y=334)

18x+18y=6012 Eqn 3

Subtracting Eqn 3 from Eqn 2

(18x+24y)-(18x+18y)=7320-6012

18x+24y-18x-18y=1308

6y=1308

$\frac{6y}{6}=\frac{1308}{6}\\y=218$

Therefore,

218 students purchased tickets at the dance.

5 0

3 years ago

Please help me with this question!!

ziro4ka [17]

Your answer would be A.) False; either both are right or one is obtuse

Two acute angles added could never equal 180

Hope this helps!

5 0

3 years ago

What is the area of the rectangle?

almond37 [142]

Take a look at the picture i sent you

8 0

3 years ago

Read 2 more answers

Jenny opened a package of screws quickly and many of them spilled on the floor. She needs to organize the fasteners according to

hichkok12 [17]

We have to compare diameters and arrange them in order smallest to greatest

We can see units for option A and B are in square inches so they represents area. So first we will find diameter from area using formula

$A = \pi r^{2}$

so for choice (A) area is given as $4.375 \times 10^{7}$ . So plug this in A place in formula and then solve for radius r

$4.375 \times 10^{7} = \pi r^{2}$

$\frac{4.375 \times 10^{7}}{\pi} = \frac{\pi r^{2}}{\pi}$

$1.393 \times 10^{7} } = r^{2}$

$\sqrt{1.393 \times 10^{7}} = \sqrt{r^{2}}$

3731.76 = r

So screw A will have
$diameter = 2 \times r = 2 \times 3731.76 = 7463.52$ inches

Similarly for choice (E) area is $1.428 \times 10^{1} = 14.28$
so again plug in formula

$A = \pi r^{2}$

$14.28 = \pi r^{2}$

$\frac{14.28}{\pi} = \frac{\pi r^{2}}{\pi}$

$4.5477 = r^{2}$

$\sqrt{4.5477} = \sqrt{r^{2}}$

2.13201 = r

So screw E will have
$diameter = 2 \times r = 2 \times 2.13201 = 4.26402$ inches

So diameters of all screws are as follows:

Screw A: 7463.52 inches
Screw B: 1.5 inches
Screw C: $1\frac{7}{8} = \frac{1\times 8+7}{8} = \frac{15}{8} = 1.875$ inches
Screw D: 0.25 inches
Screw E: 4.26402 inches

Comparing all numbers 7463.52, 1.5, 1.875, 0.25, 4.26402 we can see that smallest number is 0.25, then comes 1.5, then 1.875 and then 4.26402 and then 7463.52

So order from least to greatest will be screw D (0.25), B(1.5), C(1.875), E (4.26402), A (7463.52).

So thats the order D,B,C,E,A and the final answer