To test if this is a right triangle, let's test these side lengths with the Pythagorean Theorem.
a^2 + b^2 = c^2
c is the hypotenuse, the longest side of a right triangle.
a and b are the legs of the right triangle.
a = 7
b = 15
c = 17
7^2 + 15^2 = 17^2 ?
49 + 225 = 289 ?
274 ≠ 289
Thus, this triangle is not a right triangle since it does not satisfy the Pythagorean Theorem.
Have an awesome day! :)
Let's x represents the first odd integer
The next consecutive integer would be represented as x+2.
So x and x+2 being multiplied together will give us 1443:
(x)(x+2)=1443
x^2+2x=1443
x^2+2x-1443=0
By solving the quadratic equation using the quadratic formula, x will equal to 37 and -39.
Since the problem says "integers", so I'm assuming two pairs of consecutive integers would be ok.
With that said you 1st pair will be: 37,39
Your second pair will be: -37,-39.
Answer:
The length of KH is 6 units and OH is 6.3 units.
Step-by-step explanation:
Given the figure with lengths LO=5 and OK=4. we have to find the length of OH and KH.
In ΔLOH
By Pythagoras theorem
→ (1)
In ΔKOH,
→ (2)
In ΔKHL,
Using eq (1) and (2), we get
⇒ 
⇒ 
Put the above value in eq 2, we get
⇒ KH=6 units.
Answer:
y = (3/2)x + 8
Step-by-step explanation:
Make it into y = form so...
3x - 2y = -16
-2y = -3x - 16 (subtract 3x from both sides)
y = 
x + 8 (divide both sides by -2)
Answer:
0.5 = 3
1.5 = 9
4.5 = 27
Step-by-step explanation:
