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3 years ago

11

Suppose you put $750 into a bank account today. interest is paid annually and the rate is 3%. calculate the future value of the

$750 after 5 years.

1 answer:

inn [45]3 years ago

6 0

750 times 5 go do that hoped it helped

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What the hell is a rotation?

LekaFEV [45]

Answer:

A rotation is when a shape rotates across the x or y axis on a coordinate plane :)

Step-by-step explanation:

4 0

3 years ago

Graph the function rule:<br> Y = 3/2x + 3 HELP! Someone please explain how as well??

bulgar [2K]

Answer:

Step-by-step explanation:

the y intercept is 3 and the slope is 3/2

so you go up 3 from the y intercept and 2 to the right

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3 years ago

Find the missing lengths: <br> HI=7 and LH=9, find LK.

Katarina [22]

Answer:

LK=12

Step-by-step explanation:

From the given figure, HI=7 and LH=9, and we know that

$(KH)^{2}=(IH)(HL)$

$(KH)^{2}=7{\times}9$

$(KH)^{2}=63$ (1)

Now, from ΔKHL, we have

$(OH)^{2}=(OK)(OL)$

and from ΔOKH,

$(KH)^{2}=(OH)^{2}+(OK)^2$

$(OK)^2=(KH)^2-(OH)^2$

$(OK)^2=63-(OK)(OL)$

$(OK)^2+(OK)(OL)=63$

$OK(OK+OL)=63$

$OK(KL)=63$ (2)

Also, ΔIKL is similar to ΔOHL, therefore

$\frac{OL}{KL}=\frac{9}{16}$

$\frac{KL-OK}{KL}=\frac{9}{16}$

$\frac{KL-OK}{KL}=\frac{9}{16}$

$1-\frac{OK}{KL}=\frac{9}{16}$

$\frac{7}{16}=\frac{OK}{KL}$

Using equation (2), we get

$\frac{7}{16}=\frac{63}{(KL)^2}$

$(KL)^2=\frac{1008}{7}$

$(KL)^2=144$

$KL=12$

Thus, the value of LK is 12.

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3 years ago

Identify each point as a solution of the system or not a solution of the system.

lubasha [3.4K]

Answer:

see below

Step-by-step explanation:

Plot the points on the given graph. The ones that fall in on a solid line at the edge of the doubly-shaded area, or fall in the doubly-shaded area, are part of the solution set.

(0, 4) on the dashed line — not a solution

(-2, 4) on red line in blue area — solution

(0, 5) in doubly-shaded area — solution

(–2, 7) in doubly-shaded area — solution

(–4, 1) in blue area — not a solution

(–1, 1) on red line outside blue area — not a solution

(–1.5, 3.5) in doubly-shaded area — solution

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3 years ago

Find the value of sin 0 in each of the following figures.

alexdok [17]

Answer:

sinθ = $\frac{8}{10}$

Step-by-step explanation:

sinθ = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AC}$ = $\frac{8}{10}$

5 0

3 years ago

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