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34kurt
3 years ago
12

W+3= w+6 i need the correct step by step

Mathematics
1 answer:
Ymorist [56]3 years ago
8 0
You can subtract both sides by w then you are left with 3 = 6, which is false equation.

So there is no solution.

Hope this helps.
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The answer would be 0.36
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Which of the following could be points on the unit circle: A. (4/3, 4/5) B. (5/13, 12/13)
IRINA_888 [86]

Answer:

Option (2) and (4) are correct.

(\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

Step-by-step explanation:

Given : Some points of circles.

We have to choose which points could be points on the unit circle.

We know, the equation of circle is

x^2+y^2=r^2  ..........(1)

where r is radius of circle.

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1) (\frac{4}{3},\frac{4}{5} )

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(\frac{4}{3})^2+(\frac{4}{5})^2

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2) (\frac{5}{13},\frac{12}{13} )

Put  in LHS of  (1) , we have,

(\frac{5}{13})^2+(\frac{12}{13})^2

Simplify, we have,

=\frac{25}{169}+\frac{144}{169}

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Thus, (\frac{5}{13},\frac{12}{13} ) is a point on the unit circle.

3) (\frac{1}{3},\frac{2}{3} )

Put  in LHS of  (1) , we have,

(\frac{1}{3})^2+(\frac{2}{3})^2

Simplify, we have,

=\frac{1}{9}+\frac{4}{9}

=\frac{5}{9}\neq 1

Thus,  (\frac{1}{3},\frac{2}{3} ) is not a point on the unit circle.

4)  (\frac{6}{7},\frac{\sqrt{13}}{7} )

Put  in LHS of  (1) , we have,

(\frac{6}{7})^2+(\frac{\sqrt{13}}{7})^2

Simplify, we have,

=\frac{36}{49}+\frac{13}{49}

=\frac{49}{49}= 1

Thus,  (\frac{6}{7},\frac{\sqrt{13}}{7} ) is a point on the unit circle.

Thus, (\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

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Answer:

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Variable cost are cost that changes with production such as cost of raw material, cost of labor.

From the question:

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Answer:

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