Answer: I'm sorry I don't know but il try and calculate the answer for you
Step-by-step explanation:
AABC has vertices at (1,5), (4,8), and (16, 12). A second triangle, ADEF, has vertices at (4, 20), (16, 32), and (64, 48). If th
navik [9.2K]
Answer: the first one
Step-by-step explanation:
(x,y)->(4x, 4y)
First solve the length of side BC, CD, EF and FA
Since BC = CD = sqrt( 10^2 + 10^2)
BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2)
= 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607
= 93
The area is made up be triangle FAE, rectangle ABDE and
triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>
Angle B equals angle D
angle A equals angle C
so △ABE =△CDE
i think thats the answer