Step-by-step explanation:
Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues
Here, we have

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.
Since, we don't want x to be 0,
We have a removable discontinuity at x=0
Now, we have

We don't want the denomiator be zero because we can't divide by zero.
so


So our domain is
All Real Numbers except-2 and 0.
The vertical asymptors is x=-2.
To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of
The leading coeffixent of the numerator/ the leading coefficent of the denomiator.
So that becomes

So we have a horinzontal asymptofe of 2
Assuming you want to solve for x the result can vary. The result can be shown in multiple forms. Hope this helps!
Inequality Form:
−5≤x≤2
Interval Notation:
[−5,2]
Answer:
1st One- 1 13/30
2nd One- 1 13/20
3rd One- 1/6
Step-by-step explanation:
Because yes
-x+3x=2x
2x=2+6
2x=8
8/2=4
x=4