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3 years ago

14

Factorise fully 16c^4p^2+20cp^3

2 answers:

DiKsa [7]3 years ago

4 0

Given the expression below:

$\large \boxed{16 {c}^{4} {p}^{2} + 20c {p}^{3} }$

We can factor out c-term, p² and 4 (from 16 and 20)

$\large{4c {p}^{2} (4 {c}^{3} + 5p)}$

Answer

4cp²(4c³+5p)

FrozenT [24]3 years ago

3 0

Answer:

Step-by-step explanation:

16c^4p^2 + 20cp^3

take common

=4cp^2(4c^3 + 5p)

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HELP ME ANSWER THIS QUESTION QUICKLY BEFORE KATIE REMOVES IT FOR SOME RANDOM REASON.

Marrrta [24]

Answer:

$\vec{BC}=2b - 4a$

$\vec{XY}=a+ b$

$\vec {CY}=a - 2b$

Step-by-step explanation:

By the triangular law of vector addition:

$\vec {CY}=\vec {CA}+ \vec{AY}$

$\vec {CY}=a - 2b$

We have that;

$\frac{YB}{AY} = \frac{3}{1}$

$\implies YB = 3 AY \\ \vec {YB} = 3 \vec {AY}$

$\vec {YB} = 3 a$

From triangle ABC,

$\vec{BC}=\vec{BA}+\vec{AC} \\ \vec{BC}=2b - 4a$

Again from triangle XYB

$\vec{XY}=\vec{YB}+\vec{BX} \\$

$\vec{XY}=\vec{YB}+ \frac{1}{2} \vec{BC}$

$\vec{XY}=3a+ \frac{1}{2} (2b - 4a)$

$\vec{XY}=3a+ b - 2a \\ \vec{XY}=a+ b$

4 0

3 years ago

What is the value of m, if the equation my2+2y−4=0 has exactly one root?

stich3 [128]

Answer:

$m=\frac{-1}{4}$

Step-by-step explanation:

A quadratic equation has one root if the discriminant is 0.

That is we need $b^2-4ac=0$ for this particular question.

Compare the following to find $a,b, \text{ and } c$ :

$ax^2+bx+c=0$

$my^2+2y-4=0$

The variable $x$ is representative of the variable $y$ here.

$a=m$

$b=2$

$c=-4$

Plug in into $b^2-4ac=0$ :

$(2)^2-4(m)(-4)=0$

$4+16m=0$

Subtract 4 on both sides:

$16m=-4$

Divide both sides by 16:

$m=\frac{-4}{16}$

Reduce:

$m=\frac{-1}{4}$

6 0

3 years ago

Read 2 more answers

NEED ASAP!!!!!!!!!!!!. Multiply and express the result in scientific notation:

Snezhnost [94]

Your answer is 8.4 X 10^7.

Hope this helped!

4 0

3 years ago

Select the vertical asymptote(s) of the function <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B%28x%2B6%29%28x-1%29%7D%

Bess [88]

Answer:

As the described function, we want to find vertical asymtotes, we find the value of x so that the denominator is equal to 0.

Here, (x - 2)(x + 6) = 0

=> x = 2, x =-6

=> Option C is correct.

Hope this helps!

:)

4 0

3 years ago

Read 2 more answers

Polygon D is a scaled copy of polygon C using a scale factors of 6

Vladimir79 [104]

Answer: The area of the Polygon D is 36 times larger than the area of the Polygon C.

Step-by-step explanation:

<h3> The complete exercise is: "Polygon D is a scaled copy of Polygon C using a scale factor of 6. How many times larger is the area of Polygon D than the area Polygon C"?</h3>

In order to solve this problem it is important to analize the information provided in the exercise.

You know that the Polygon D was obtained by multiplying the lengths of the Polygon C by the scale factor of 6.

Then, you can identify that the Length scale factor used is:

$Length\ scale\ factor=k=6$

Now you have to find the Area scale factor.

Knowing that the Length scale factos is 6, you can say that the Area scale factor is:

$Area \ scale\ factor=k^2=6^2$

Finally, evaluating, you get that this is:

$Area \ scale\ factor=36$

Therefore, knowing the Area scale factor, you can determine that the area of the Polygon D is 36 times larger than the area of the Polygon C.

8 0

3 years ago