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hjlf
3 years ago
14

Factorise fully 16c^4p^2+20cp^3​

Mathematics
2 answers:
DiKsa [7]3 years ago
4 0

Given the expression below:

\large \boxed{16 {c}^{4}  {p}^{2}  + 20c {p}^{3} }

We can factor out c-term, p² and 4 (from 16 and 20)

\large{4c {p}^{2} (4 {c}^{3}  + 5p)}

Answer

  • 4cp²(4c³+5p)

FrozenT [24]3 years ago
3 0

Answer:

Step-by-step explanation:

16c^4p^2 + 20cp^3

take common

=4cp^2(4c^3 + 5p)

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Zinaida [17]

<u>We are given:</u>

The function: y = -16t² + 64

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<u>Part A:</u>

when the droplet would hit the ground, it's height from the ground will be 0

replacing that in the given function:

0 = -16t² + 64

16t² = 64                          [adding 16t² on both sides]

t² = 4                                [dividing both sides by 16]

t = 2 seconds                  [taking square root of both sides]

<u>Part B:</u>

for second droplet,

height from ground = 16 feet

time taken = t seconds

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iVinArrow [24]

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