Question

Factorise fully 16c^4p^2+20cp^3​

Answer 1

Given the expression below:

$\large \boxed{16 {c}^{4} {p}^{2} + 20c {p}^{3} }$

We can factor out c-term, p² and 4 (from 16 and 20)

$\large{4c {p}^{2} (4 {c}^{3} + 5p)}$

Answer

• 4cp²(4c³+5p)

Answer 2

Answer:

Step-by-step explanation:

16c^4p^2 + 20cp^3

take common

=4cp^2(4c^3 + 5p)