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Whitepunk [10]
3 years ago
7

8x+5=7x+1 this is my question

Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0

Answer: x=-4

Step-by-step explanation: first you collect like terms 8x-7x=1-5 then we do 8x-7x which would equal 1x or just x next we do 1-5 which equals 4 so the solution to this equation is x=-4

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1. Type your answer below. 2. Type your answer below (no spaces! for example x=19) 3. Type your answer below (no spaces! for exa
Nookie1986 [14]

Answer:

1) 12

2) c=-25

3) x = -16 2/3

Step-by-step explanation:

1) ..........................

  • 6*(4-10+8) =
  • 6*(- 6+8) =
  • 6*2=
  • 12

2) ..........................

  • 34 + 2c = -16
  • 2c = - 16 -34
  • 2c = -50
  • c = -50/2
  • c=-25

3) ..........................

  • 40 = -3x - 10
  • 40+ 10 = -3x
  • -3x = 50
  • x = 50/-3
  • x=-16 2/3
3 0
3 years ago
There can be more than one option answer fast in two minutes
olasank [31]

Answer:

QR and SV

RS and TU

Step-by-step explanation:

3 0
3 years ago
There are 10 balls in an urn, numbered from 1 to 10. If 5 balls are selected at random and their numbers are added, what is the
Kisachek [45]

Let B_i denote the value on the i-th drawn ball. We want to find the expectation of S=B_1+B_2+B_3+B_4+B_5, which by linearity of expectation is

E[S]=E\left[\displaystyle\sum_{i=1}^5B_i\right]=\sum_{i=1}^5E[B_i]

(which is true regardless of whether the X_i are independent!)

At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.

P(X_i=x)=\begin{cases}\frac1{10}&\text{for }x\in\{1,2,\ldots,10\}\\0&\text{otherwise}\end{cases}

and so

E[X_i]=\displaystyle\sum_{i=1}^{10}x\,P(X_i=x)=\frac1{10}\frac{10(10+1)}2=5.5

Then the expected value of the total is

E[S]=5(5.5)=\boxed{27.5}

8 0
3 years ago
Find the sum of -3a + 2 and 5a - 3
Anon25 [30]

Answer

-1(3a-2)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
HELP DUE TODAY
Fudgin [204]
I think it is D
Hope my answer help you?
6 0
3 years ago
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