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zavuch27 [327]
3 years ago
9

In 2002, Takaru Kobyashi ate fifty hot dogs in twelve minutes. At that rate, and assuming that he wouldn’t explode, how many dog

s could Takaru eat in an hour?
Mathematics
1 answer:
kupik [55]3 years ago
5 0
So he ate 50 in 12 minutes. 
There are 60 minutes in an hour. You want to divide 12 into 60 minutes.
Multiply your answer on 5 times the number of Hog-Dogs.
= 250 Hot-Dogs 
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Answer:

D(2,2)

Step-by-step explanation:

The diagonals of a parallelogram gram bisects each other.

Therefore E is the midpoint of AD.

Let the coordinates of D be (a,b).

By the midpoint rule:

( \frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}) = ( - 2, \frac{1}{2} )

This implies that:

( \frac{ - 6+a}{2} ,\frac{ - 1+b}{2}) = ( - 2, \frac{1}{2} )

This implies that:

( \frac{ - 6+a}{2} =  - 2 ,\frac{ - 1+b}{2} =  \frac{1}{2} )

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3 years ago
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Rudik [331]

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(6,0) I think

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Valentin [98]

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//

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//

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