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Alex787 [66]
3 years ago
12

Find all the zeros of each equation.

Mathematics
1 answer:
Dimas [21]3 years ago
8 0
ANWSER is B my dude, hope this helped Trump 2020
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PLEASE HELP: Simplify the expression. Write your answer as a power. 5^2⋅5^9/5
antoniya [11.8K]

Answer:

9.765625×10^6

Step-by-step explanation:

Simplify the following:

5^2×5^9/5

Hint: | Express 5^2×5^9/5 as a single fraction.

5^2×5^9/5 = (5^2×5^9)/5:

(5^2×5^9)/5

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to (5^2×5^9)/5.

Combine powers. (5^2×5^9)/5 = 5^(9 + 2 - 1):

5^(9 + 2 - 1)

Hint: | Evaluate 9 + 2.

9 + 2 = 11:

5^(11 - 1)

Hint: | Subtract 1 from 11.

| 1 | 1

- | | 1

| 1 | 0:

5^10

Hint: | Compute 5^10 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

5^10 = (5^5)^2 = (5×5^4)^2 = (5 (5^2)^2)^2:

(5 (5^2)^2)^2

Hint: | Evaluate 5^2.

5^2 = 25:

(5×25^2)^2

Hint: | Evaluate 25^2.

| 2 | 5

× | 2 | 5

1 | 2 | 5

5 | 0 | 0

6 | 2 | 5:

(5×625)^2

Hint: | Multiply 5 and 625 together.

5×625 = 3125:

3125^2

Hint: | Evaluate 3125^2.

| | | 3 | 1 | 2 | 5

× | | | 3 | 1 | 2 | 5

| | 1 | 5 | 6 | 2 | 5

| | 6 | 2 | 5 | 0 | 0

| 3 | 1 | 2 | 5 | 0 | 0

9 | 3 | 7 | 5 | 0 | 0 | 0

9 | 7 | 6 | 5 | 6 | 2 | 5:

Answer: | 9765625 = 9.765625×10^6

7 0
2 years ago
It is a well-known fact that 50% of the general population are rascals (P(R) = 0.5) and 50% of the general population are not ra
aleksley [76]

Answer:

The answer is D. 0.75

Step-by-step explanation:

Let call R the event that a person is rascal, RC a person is not rascal, TH a person use top hat and NTH a person don’t use top hat.  

From the information on the question we have 4 options with their respective probability:

1. A person could be rascal and use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and use a top hat (0.9), then:

P(R y TH)=0.5*0.9=0.45

2. A person could be rascal and don’t use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and not use a top hat (0.9), then:

P(R y NTH)=0.5*0.1=0.05

3. A person could be not rascal and use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and use a top hat (0.3), then:

P(RC y TH)=0.5*0.3=0.15

4. A person could be not rascal and not use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and not use a top hat (0.7), then:

P(RC y NTH)=0.5*0.7=0.35

Then the probability that a person is a rascal given that he is wearing a top hat could be written and calculate as:

P(R/TH)=\frac{P(R y TH)}{P(TH)}

For calculate P(TH) we need to sum all the option in which TH is involve so:

P(TH) = P(R y TH)+ P(RC y TH)

P(TH)=0.45+0.15=0.6

Replacing values on the first equation we get:

P(R/TH)=\frac{0.45}{0.6} =0.75

So, the probability that a person is a rascal given that he is wearing a top hat is 0.75

5 0
4 years ago
A donation center has 44 small bins with 24 caned food in them they wanna give each food bank the same amount of food there are
denpristay [2]

Complete question :

A donation center has 44 small bins with 24 caned food in them they wanna give each food bank the same amount of food there are 4 food banks. How many cans should they give to each food bank?

Answer:

264 cans

Step-by-step explanation:

Number of bins = 44

Number of canned food per bin = 24

Total number of canned foods = (number of bins * number of canned food per bin)

Total number of canned foods = 44 * 24 = 1056

Food is to be distributed equally among 4 banks :

Number of food per bank = 1056 / 4 = 264

6 0
3 years ago
List the 4-digit numbers that fit these clues
eimsori [14]
What are the clues fvfrce
6 0
4 years ago
Determine if the relation shown in the graph is symmetrical with respect to the x-axis, y-axis, or the origin.
Debora [2.8K]
Yes i would say it is symmetrical
5 0
3 years ago
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