Find all the zeros of each equation.

Mathematics

1 answer:

Dimas [21]2 years ago

8 0

ANWSER is B my dude, hope this helped Trump 2020

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scoundrel [369]

Answer:

$9^{\frac{3}{2}}=\sqrt{9^3}=27$

Step-by-step explanation:

The fractional exponent m/n is often translated to radical form as ...

$x^{\frac{m}{n}}=\sqrt[n]{x^m}$

In this case, I find it easier to evaluate as ...

$x^{\frac{m}{n}}=(\sqrt[n]{x})^m=\boxed{(\sqrt{9})^3=3^3=27}$

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Digit 4 in 49,308 is ten thousands and the 4in 4061 is thousands

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Suppose y varies directly with x. if y=-3 when x=5 find y when x=-1

Scrat [10]

$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x

&& y={{ k }}x
\end{array}
\\ \quad \\
\textit{we know that, when}
\begin{cases}
y=-3\\
x=5
\end{cases}\implies y=kx\implies (-3)=k(5)$

solve for "k", to find the "constant of variation",
then plug it back in the y = kx, to get the equation
now
what's is y when x = -1?
well, just plug that in the equation with the found "k" value,
to get "y" :)

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