2 years ago

$1,000 invested at 8% compounded semiannually after a period of 2 years

Mathematics

1 answer:

rusak2 [61]2 years ago

7 0

Answer:

1160 will be the new amount after 2 years

Step-by-step explanation:

P = $1000, t = 2 years, r = 0.08.

A = 1000(1+0.08(2)) = 1000(1.16) = 1160

Therefore 1160 is the new amount after two years.

You might be interested in

Barbara has $70.00 in her pocket and a $20 gift card. Which purchase will she be able to make without having to use her credit c

suter [353]

Yes depending on her purchase. If it is over 90.00 dollars then no she will not.

3 0

3 years ago

what is the y-intercept of the function, represented by the table of values below x= -2,1,2,4,7 y=15,6,3,-3,-12

Natali5045456 [20]

Answer: The y-intercept would be 10

Step-by-step explanation:

(-2, 15), (1, 6), (2, 3), (4, -3), (7, -12) are the coordinate points, you can graph it to find the intercept. I used the graphing calculator desmos.

4 0

3 years ago

Read 2 more answers

A clothing store is raising the price of all it’s sweaters by three dollars right now expression that could be used to find the

S_A_V [24]

D+3=N
N=amount of new price

7 0

3 years ago

What is 8% of 200 estimated?

chubhunter [2.5K]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What is the value of R

frutty [35]

Answer:

2.45 × $10^{6}$

Step-by-step explanation:

using the rules of exponents

• $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$

• $(a^m)^{n}$ = $a^{mn}$

evaluating the numerator

(3.8 × $10^{5}$ )² = 3.8² × $(10^5)^{2}$ = 14.44 × $10^{10}$

R = $\frac{14.44.10^{10} }{5.9.10^{4} }$

= $\frac{14.44}{5.9}$ × $\frac{10^{10} }{10^{4} }$

= 2.45 × $10^{6}$ ← to 2 dec. places

7 0

2 years ago