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noname [10]
3 years ago
11

Find the distance between the parallel lines m and n whose equations are

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectively.

There are several ways to do this...here's one

Let (0, 4) be a point on the first line

Then.......a line with a negative reciprocal slope going through this point will have the equation :

y = -x + 4........so......we can find the intersection of this line with y = x - 6....set both equations equal

-x + 4  = x - 6   add x, 6 to both sides

10 = 2x     divide both sides by 2

5  = x

So...using -x + 4, the y value  at intersection  = -1.......

So...we just need to find the distance from  (0,4)  to ( 5, -1)  =

√[ (5)^2 + (4 + 1)^2 ] =  5√2  ≈  7.07 units

Here's a pic....AB is the distance  with A = (0,4)  and B = (5, -1)

Step-by-step explanation:

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(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

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(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

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Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

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n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

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Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

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