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Brut [27]
3 years ago
5

Complete the equation for the standard form of the line that has an x-intercept of –4 and a y-intercept of 3

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

The equation for the standard form of the line will be:

  • 3x + (-4y) = -12

Step-by-step explanation:

Given

  • x-intercept = –4
  • y-intercept = 3

The equation of a line in standard form

  • Ax + By = C

where A is a positive integer and B, C are integers

We know the equation of a line in  slope-intercept form

y = mx+b

where m is the slope and b the y-intercept

To calculate the slope, use the gradient formula

m = y₂-y₁ / x₂-x₁

let  

(x₁, y₁) = (-4, 0)             ∵ x-intercept = (-4, 0)

(x₂, y₂) = (0, 3)              ∵ y-intercept = (0, 3)

m = y₂-y₁ / x₂-x₁

    = (3 - 0) / (0 - (-4))

    = 3 / 4

Thus, the equation in slope-intercept form:

y = mx+b

y = 3/4x + 3

  • Writing in standard form

Multiply y = 3/4x + 3 by 4

4y = 3x + 12

3x-4y = -12

3x + (-4y) = -12

Thus, the equation for the standard form of the line will be:

  • 3x + (-4y) = -12

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Answer:

Speed of the plane in still air: 779\; {\rm km \cdot h^{-1}}.

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Step-by-step explanation:

Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

  • When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be (x - y)\; {\rm km \cdot h^{-1}}.
  • When this plane is travelling in the same direction as the wind, the ground speed of this plane would be (x + y)\; {\rm km \cdot h^{-1}}.

The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

Similarly, since the plane travels 7911\; {\rm km} in 9\; {\rm h} when travelling in the same direction as the wind (v = (x + y)\; {\rm km \cdot h^{-1}},) 9\, (x + y) = 7911.

Add the two equations to eliminate y. Subtract the second equation from the first to eliminate x. Solve this system of equations for x and y: x = 779 and y = 100.

Hence, the speed of this plane in still air would be 779\; {\rm km \cdot h^{-1}}, whereas the speed of the wind would be 100\; {\rm km \cdot h^{-1}}.

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The area of a floor to be carpeted is 2700 square feet what is this area in square yards?
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