Answer:
31 is a prime number.
How to tell if a number is prime: estimate the square root. In this case, we know the square root of 31 is between 5 and 6 and it isn’t divisible by either of those. If it is divisible by a number higher than it’s square root, the other factor must be lower. Is it divisible by 4 or 2? no, because it isn’t an even number. It’s not divisible by 3, because there’s a remainder of 1 if you try. You’ve eliminated all numbers less than the square root, so it is prime
Answer:
your answer will be <em><u>A. 38.5°</u></em>
Step-by-step explanation:
m<ZYW=1/2(77)
<u>=38.5</u>
<u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u>.</u><u>.</u>
Answer:
See below
Step-by-step explanation:
<h3>Graphing:</h3>
we are given two functions
where f(x) is a <em>linear</em><em> </em><em>function</em> and g(x) is a <em>q</em><em>uadratic </em>function
we want to figure out the solutions of the function
let's graph f(x):
the Black-table is attached
let's graph g(x):
the picture is attached
hence, the graph should be
the graph is attached
<h3>solutions stating:</h3>
so we need solution(s) which satisfy(ies) the both functions
in this case the solution (s) the x coordinate(s) where both functions intercept we get from the graph that both functions intercept at <u>(</u><u>-</u><u>1</u><u>,</u><u>6</u><u>)</u> and <u>(</u><u>3</u><u>,</u><u>2</u><u>)</u>
hence,
x={-1,3}
Answer:
The remainder = 13.
Step-by-step explanation:
By the Remainder Theorem the remainder when the function is divided by
x - 1 is f(1).
f(1) = 4(1)^3 + 4(1)^2 + 2(1) + 3
= 4 + 4 + 2 + 3
= 13.
So x - 1 is not a factor of f(x).
If it was a factor the remainder would be 0.
