I'm assuming the 2x2y means 2 x squared y
in that case you just pick the biggest factors that both of those share 2xy and 2x^2y both share a common factor of 2xy.
Answer: Graphing a Quadratic Function
y=−10x2−31x
Step-by-step explanation:
Graphing a Quadratic Function
f(x) ÷ x - k.
9) f(x) = x' - 8x? - 10x² – 24x
Answer:
The end of the stencil is located at (8, -1)
Step-by-step explanation:
The given parameters are;
Location of the beginning of the left edge of the stencil = (-1, 2)
Location of the detail = (2, 1)
Ratio of detail distance from beginning to detail to distance from beginning to stencil end = 1:2
Distance from beginning to detail = √((-1 - 2)² + (2 - 1)²) = √10
Given that the ratio of the length of the detail to the length of the end after the detail is 1:2 therefore;
√10:Length of stencil side = 1:2
Distance from detail to stencil end = 2×√10
Which gives;
Slope of line = tan⁺¹((2 - 1)/(-1 - 2)) = tan⁺¹(-1/3) = -18.435°
x-coordinates of the end of the stencil = 2√10 × cos(-18.435°) + 2 = 8
y coordinates of the end of the stencil = 2√10 × sin(-18.435°) + 1 = -1
The coordinates of the end of the stencil = (8, -1)
Answer:
The value of m is 3
Step-by-step explanation:
We are given that ABCD is a parallelogram
Property of parallelogram : Opposite sides of parallelogram is equal
So, AB = CD and BC = AD
We are given that
BC =3m + 10
AD = 7m – 2
So, Using Property
BC=AD
3m+10=7m-2
12=4m
3=m
Hence The value of m is 3
