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goldenfox [79]
3 years ago
5

Distance, Midpoint, Circles - What is the equation of the circle? WILL GIVE BRAINLIEST!

Mathematics
1 answer:
elixir [45]3 years ago
5 0

Answer:

(x-4)^2 + (y-3)^2 =8

Step-by-step explanation:

The midpoint of the diameter is (6+2)/2= 4, (5+1)/2 = 3

(4,3)

The radius is the distance from the midpoint to an endpoint

This is 2sqrt(8)

So the equation is

(x-4)^2 + (y-3)^2 =8

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Answer:

a. \:  \:  \frac{ {4x}^{6} }{ {y}^{3} }  \\

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Step-by-step explanation:

<h3>a. </h3>

{( {4x}^{ - 2} y)}^{ - 3}  \\  {4x}^{ - 2 \times  - 3}  \:  \: {y}^{1 \times  - 3}  \\  {4x}^{6}  {y}^{ - 3}  \\  \frac{ {4x}^{6} }{ {y}^{3} }  \\

<h3>b.</h3>

{( {8x}^{6} {y}^{ - 3})  }^{ \frac{1}{2} }  \\  {8x}^{6 \times  \frac{1}{2} } \:  \:  {y}^{ - 3 \times  \frac{1}{2} }   \\  {8x}^{3}  {y}^{  - \frac {3}{2} }  \\  \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\

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