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KiRa [710]
3 years ago
11

Please help me answer this question. First to answer will be marked braineist. NO WORK NESSACARY. Thank you ☺️

Mathematics
2 answers:
Nutka1998 [239]3 years ago
4 0

i did the work and the answer is f(x) = 3x+3

shusha [124]3 years ago
4 0

Yeah this guy above me is right, I took Algebra 1 Honors so I think I'd know. If someone in the future needs the work, all you really need to do to figure this out is input the x coordinate found in the (x,y) so for example (0, 3) into the equation f(x) = 3x + 3 so...

f(x) = 3 (0) + 3  = f(x) = 3 WHATEVER YOU HAVE LEFT IS THE Y COORDINATE SO YOU KNOW WHEN YOU INPUT X INTO THE EQUATION YOU WILL FIND Y WHICH IS 3 (0, 3).

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6 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
2 years ago
For what real values of does the quadratic 12x^2+k*x+27=0 have nonreal roots
icang [17]

Step-by-step explanation:

Discriminant : k² - 4(12)(27) < 0

So k² - 1296 < 0, -36 < k < 36.

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2 years ago
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Answer:

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Step-by-step explanation:

If this was an equation...

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So we convert that into an inequality.

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3 years ago
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