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kozerog [31]
3 years ago
11

Nick is doing some math exercises on a website called Khon Academy. In Khon Academy, you have to get at least 70%, percent of th

e problems in an exercise right in order to gain proficiency.
So far, Nick answered one question, and he didn't get it right. Suppose he answers 75%, percent of the following questions correctly and gains proficiency in the exercise.
Write an inequality in terms of that models the situation.
Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0

Answer:

0.75q/q+1 greater than or equal to .7

Step-by-step explanation:

ra1l [238]3 years ago
4 0

Answer:

0.75q/q+1 greater than or equal to .7

Step-by-step explanation:

Hope you get this! I suck at math but, hopefully I was right.

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A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ
Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation:  Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

^{10}C_r=210.

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10

If r = 2, then

^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45

If r = 3, then

^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120

If r = 4, then

^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0
4 years ago
Read 2 more answers
. The larger number is 19 more than the smaller number. What are the numbers?
ASHA 777 [7]

Answer:

1

Step-by-step explanation:

4 0
4 years ago
Simplify 3√p^4q^6r^5
jeka94

Answer:

3p^2q^3r^2√r

Step-by-step explanation:

3√p^4q^6r^5

= 3p^2q^3r^2√r

Hope that helps

3 0
3 years ago
there are 200 end of the year school dance tickets students who have perfect attendance are able to presage them in advance if 1
Umnica [9.8K]

200 - 18 = 182
182 is the answers
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3 years ago
Your monthly bill went frm 57.98 to 62.49 whats the percent change
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D is your answer for your question
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