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2 years ago

What is 9 plus 10???

Mathematics

1 answer:

Anon25 [30]2 years ago

8 0

Answer:

Here’s legitimate proof that 9+10=21

(9 + 10) (base x) = 21 (base y)

9(1) + [1(x) + 0(1)] = 2(y) + 1

Simplify and solve for y:

2y = 8 + x

y = 4 + x/2

Since we have number bases, we want x and y to be positive integers. The term x/2 requires that x be a positive even number.

Also since 9 is in base x, we have x ≥ 10, as the digit 9 would not be used for a base 9 or smaller.

Thus we have the pairs of solutions:

x = 10, so y = 9

x = 12, so y = 10

x = 14, so y = 12

…

x, y = 4 + x/2 … Therefore 9+10=21!

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This is so important please help

Shtirlitz [24]

Given:

The center of the circle = (-1,0)

Point on the circle = (2,-4).

To find:

The equation of the circle.

Solution:

Distance between two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between the center (-1,0) and the point on the circle (2,-4) is the radius of the circle.

$r=\sqrt{(2-(-1))^2+(-4-0)^2}$

$r=\sqrt{(2+1)^2+(-4)^2}$

$r=\sqrt{(3)^2+(-4)^2}$

On further simplification, we get

$r=\sqrt{9+16}$

$r=\sqrt{25}$

$r=5$

Now, the equation of the circle is

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center and r is the radius of the circle.

The radius of the circle is 5 and the center is at (-1,0), so the equation of the circle is

$(x-(-1))^2+(y-0)^2=5^2$

$(x+1)^2+y^2=25$

Therefore, the first option is correct, i.e., $(x+1)^2+y^2=25$ .

3 0

2 years ago

An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,

butalik [34]

Answer:

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

$r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t$

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

$s=\sqrt{r_{A}^{2}+r_{B}^{2}}$

Rate of change of such distance can be found by the deriving the expression in terms of time:

$\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }$

Where $\frac{dr_{A}}{dt} = 500\,\frac{mi}{h}$ and $\frac{dr_{B}}{dt} = 550\,\frac{mi}{h}$ , respectively. Distances of each airliner at 2:30 PM are:

$r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi$

$r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi$

The rate of change is:

$\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }$

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

6 0

3 years ago

Consider the polynomial function g(x)=-10x^7-9x^5+7x^3-8x.

Mandarinka [93]

Answer:

the graph rises to the left and falls to the right.

the answer is B

Step-by-step explanation:

8 0

2 years ago

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A3-b3=(a-b)(a2+an+b2) 64x6-27

olga nikolaevna [1]

a³-b³=(a-b)(a²+ab+b²)

64x⁶ - 27

64 = 4³,
x⁶ = (x²)³
27 = 3³

64x⁶ - 27 = 4³(x²)³ -3³ = (4x²)³ -3³. Now, we can use a formula where a=4x², b=3

(4x²)³ -3³ = (4x² -3)((4x²)² +4x²*3 + 3²) = (4x² -3)(16x⁴ +12x² + 9)

Answer: 64x⁶ - 27= (4x² -3)(16x⁴ +12x² + 9)

4 0

3 years ago

Write 2.14 x 10-6 in standard form.

Nadusha1986 [10]

Answer:

0.00000214

Step-by-step explanation:

7 0

3 years ago

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What is 9 plus 10???​

What is 9 plus 10???