The outcome A="At least one" means {1,2,3,4,5......n} where n is the maximum possible outcome.
The only other outcome (B) left (i.e. the complement of the above event "at least one") is (B)={0}.
Therefore, by Kolmogorov's second axiom, A and B are complements, and
P(A)+P(B)=1
therefore
P(A)=1-P(B), or in words,
Probability of outcomes of "at least one" is the complement of the outcome of "0" item.
5x - 9 ≤ 21
5x ≤ 21 + 9
5x ≤ 30
x ≤ 30 ÷ 5
x ≤ 6
A linear equation of the form :
y = mx+b
can have at the most ONE x-intercept and at the most ONE y-intercept
I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis
Combine like terms... 2s and 4s are like terms so that's 6s 4,2,3 are like terms add that up its 9. So it would look like this 6s+9
15.1 f
Step-by-step explanation:
-13.4+25.8= 15.1 F