The answer would be 7 miles. I can see that the initial charge is $35. For every mile there is a $2 fee. I found this by looking at how much the fee increases from 1 mile to 3 miles. There’s a $4 increase. So $4 divided by 2 miles is equal to 2. 1 mile is equal to $2 after the initial price. I counted by 2s from 41 to 49. Every count of 2 is a mile. When I landed on 49 I was at the 7th mile. A half of a mile is equal to $1. I know this because from 7 miles to 8.5 miles, there is a $3 increase. The 8th mile would be $51, but the half of a mile increases the cost by $1. Sorry if it’s very wordy. The answer is 7 miles though!
Let x be the number of red fish
3:5 = x:20
3/5 = x/20
(Cross method)
5x = 60
x =12
There are 12 red fish in the fish tank.
Answer:
Step-by-step explanation:

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<u>Consider</u></h2>

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<u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>




So, on substituting all these values, we get




<h2>Hence,</h2>

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<h2>ADDITIONAL INFORMATION :-</h2>
Sign of Trigonometric ratios in Quadrants
- sin (90°-θ) = cos θ
- cos (90°-θ) = sin θ
- tan (90°-θ) = cot θ
- csc (90°-θ) = sec θ
- sec (90°-θ) = csc θ
- cot (90°-θ) = tan θ
- sin (90°+θ) = cos θ
- cos (90°+θ) = -sin θ
- tan (90°+θ) = -cot θ
- csc (90°+θ) = sec θ
- sec (90°+θ) = -csc θ
- cot (90°+θ) = -tan θ
- sin (180°-θ) = sin θ
- cos (180°-θ) = -cos θ
- tan (180°-θ) = -tan θ
- csc (180°-θ) = csc θ
- sec (180°-θ) = -sec θ
- cot (180°-θ) = -cot θ
- sin (180°+θ) = -sin θ
- cos (180°+θ) = -cos θ
- tan (180°+θ) = tan θ
- csc (180°+θ) = -csc θ
- sec (180°+θ) = -sec θ
- cot (180°+θ) = cot θ
- sin (270°-θ) = -cos θ
- cos (270°-θ) = -sin θ
- tan (270°-θ) = cot θ
- csc (270°-θ) = -sec θ
- sec (270°-θ) = -csc θ
- cot (270°-θ) = tan θ
- sin (270°+θ) = -cos θ
- cos (270°+θ) = sin θ
- tan (270°+θ) = -cot θ
- csc (270°+θ) = -sec θ
- sec (270°+θ) = cos θ
- cot (270°+θ) = -tan θ
Answer:
Explain the question a little better
Step-by-step explanation:
It is hard to understand ur question. Please restate it in a better way.