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2 years ago

HELP PLZ ill upvote!!! Simon bought a $48 table on sale at 30% off.

Mathematics

1 answer:

katrin [286]2 years ago

6 0

30% off of 48 is 33.6 and that estimated is 30. So, by these naswer choices I would go for D. 30 (50)

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Form and solve an equation for x.<br> 6x +40<br> Х<br> 3x + 100

Blababa [14]

Answer:

x = 22

Step-by-step explanation:

The sum of the angles round a point is 360°

Sum the given angles and equate to 360

x + 6x + 40 + 3x + 100 = 360

10x + 140 = 360 ( subtract 140 from both sides )

10x = 220 ( divide both sides by 10 )

x = 22

5 0

2 years ago

18. Find the measure of each numbered angle.

DiKsa [7]

Answer:

m∠1 = 50°, m∠2 = 90°, m∠3 = 40°, and m∠4 = 50°

Step-by-step explanation:

Angles on straight line are equal;

$m \angle1 + 130 = 180$

$m \angle1= 180 - 130 \\ m \angle1= 50$

Vertical angles are equal,

$m \angle4= m \angle \: 1= 50 \degree$

Complementary angles add up to 90°.

$m \angle3 + m \angle4 = 90 \degree \\ 40 + m \angle3 = 90 \degree. \\ m \angle3 = 90 \degree - 50 \degree \\ m \angle3 = 40 \degree$

Angles on straight line adds up to 180°

$m \angle1 + m \angle2 + m \angle3 = 180 \degree$

$40 + m \angle2 + 50 = 180 \\ m \angle2 = 180 - 50 - 40 = 90$

7 0

3 years ago

I did this and turned it in, I got a C on it, could you tell me what to fix so I can get an A?

mart [117]

In my opinion I think your response sounds great

8 0

3 years ago

357/40 mixed number I can't figure it out

Maksim231197 [3]

Answer: 8 37/40

Step-by-step explanation:

Divide 357 by 40!?

3 0

3 years ago

Please help me thank you.

Alona [7]

Answer:

$\large\boxed{1.\ (4)^{-3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}}$

$\large\boxed{2.\ ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x}$

Step-by-step explanation:

$Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\------------\\\\(4)^{-3x^2}=\left[(4)^{-1}\right]^{3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}$

$Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\ and\ (a^n)^m=a^{nm}\\--------------------\\\\ab^{-3x}=a\cdot b^{-3x}=a\left[(b)^{-1}\right]^{3x}=a\left(\dfrac{1}{b}\right)^{3x}\\\\ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x$

8 0

2 years ago