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Allisa [31]
3 years ago
14

Find the value of x for which ABCD must be a parallelogram. (4x - 1) (x + 38)°

Mathematics
1 answer:
mart [117]3 years ago
3 0

Answer:

answer is 13

Step-by-step explanation:

13+38=51

4*13-1=51

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What is the volume of a cone with the given dimensions?<br> Diameter = 14 cm.; Height = 2 cm.
Helga [31]
Volume of a cone = (π.R²)(h/3)

Diameter = 14cm then R=7 cm

Height = h= 2cm

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4 0
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Eight friends ate at a restaurant and agreed to share the bill equally. Because Judi forgot her money, each of her seven friends
galina1969 [7]
Judi's share was  (7 x $2.50) =  $17.50 .

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5 0
3 years ago
Explain how you know if an equation has one solution, infinitely many solutions, or no solution
lubasha [3.4K]
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8 0
3 years ago
Choose the equation that best represents the standard form of the following expression x^2/2=7x
zhenek [66]

Answer:

x^2 - 14x = 0

Step-by-step explanation:

x^2/2=7x

x^2=7x * 2

x^2=14x

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7 0
3 years ago
Hawick is 1515 miles south of Abbotsford, and Kelso is 1717 miles east of Abbotsford. What is the distance from Hawick to Kelso?
Mashcka [7]

Answer:

As per the statement:

Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.

Let  H represents  Hawick , A represents Abbotsford and K represents Kelso

See the diagram as shown below:

Distance of AH = 15 miles

Distance of AK = 17 miles.

We have to find the distance HK:

Using Pythagoras theorem;

\text{Hypotenuse side}^2 = \text{Adjacent side}^2 + \text{opposite side}^2

then;

\text{HK}^2 = 15^2+17^2 = 225 + 289 = 514

or

HK = \sqrt{514} =22.671581 miles.

Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles

5 0
3 years ago
Read 2 more answers
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