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2 years ago

Find the value of x for which ABCD must be a parallelogram. (4x - 1) (x + 38)°

Mathematics

1 answer:

mart [117]2 years ago

3 0

Answer:

answer is 13

Step-by-step explanation:

13+38=51

4*13-1=51

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An ice cube is made of 5 fluid ounces of water. About how many milliliters of water does it take to make an ice cube

Sergio [31]

<u>ANSWER: </u>

147.868 mL of water is required to make an ice cube.

<u>SOLUTION: </u>

Given that, an ice cube is made up of 5 fluid ounces of water.

We need to find how many milli liters of water does it require to make an ice cube.

For, that we have to convert 5 fluid ounces in to units of milli liters.

We know that, 1 US fluid ounce equals to 29.5735 milli liters. i.e. 1 US fluid ounce = 29.5735 mL

Now,

An ice cube is made by 5 fluid ounces = 5 x 1 fluid ounce

= 5 x 29.5735 mL = 147.868 mL

Hence, 147.868 mL of water is required to make an ice cube.

5 0

2 years ago

Round 290951.867863 to the nearest hundred.

andreev551 [17]

Answer: 290951.87

Step-by-step explanation:

Hope this helps :D

5 0

2 years ago

How do I solve this twice the difference of a number and seven is less than or equal to forty

max2010maxim [7]

2 * (x-7) <= 40

x<=27

4 0

3 years ago

Read 2 more answers

The polar curve $r = 1 + \cos \theta$ is rotated once around the point with polar coordinates $(2,0).$ What is the area of the r

mash [69]

Answer:

$Area = -2.3147$

Step-by-step explanation:

Given

$r = 1 + \cos \theta$

Required

Determine the area with coordinates $(2,0)$

The area is represented as:

$Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta$

Where

$r = 1 + \cos \theta$

and

$(a,b) = (2,0)$

Substitute values for r, a and b in

$Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta$

$Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)^2} \, d\theta$

Expand

$Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)(1 + cos\theta)} \, d\theta$

$Area = \frac{1}{2}\int\limits^0_2 {(1 + 2cos\theta+cos^2\theta} )\, d\theta$

By integratin the above, we get:

$Area = \frac{1}{2}*\frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{2}[0,2]$

$Area = \frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{4}[0,2]$

Substitute 0 and 2 for $\theta$ one after the other

$Area = \frac{(cos(0) + 4)sin(0) + 3*0}{4} - \frac{(cos(2) + 4)sin(2) + 3*2}{4}$

$Area = \frac{(cos(0) + 4)sin(0)}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = \frac{(1 + 4)*0}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = \frac{-sin(2)(cos(2) + 4) - 6}{4}$

Get sin(2) and cos(2) in radians

$Area = \frac{-0.9093 * (-0.4161 + 4) - 6}{4}$

$Area = \frac{-9.2588}{4}$

$Area = -2.3147$

3 0

2 years ago

A study shows that 84% of the population of all calculus students consider calculus an exciting subject. Suppose 29 students ar

ratelena [41]

Answer:

P = 0.041553

Step-by-step explanation:

Probability that a student considers calculus exciting. = 0.84

Probability that a student finds calculus not exciting = 0.16

This is a binomial experiment.

p = 0.84 and n = 29

The probability of observing 28 or more of the students who consider calculus to be an exciting subject in our sample of 29 is given by:

$\left(\begin{array}{ccc}29\\28\end{array}\right) .0.84^{28} .0.16^{1}+\left(\begin{array}{ccc}29\\29\end{array}\right) .0.84^{29} .0.16^{0}$

P = 0.041553

5 0

3 years ago