All categories

3 years ago

How do i solve 426 to nearest ten

2 answers:

6 0

426 to nearest ten is 430 because the rule is 1-4 is rounded to the 0 and 5-9 is rounded to the ten place. You just basically look at the place value and round it.

puteri [66]3 years ago

5 0

We look at the tens place

20 is in the tens place

now look at the Ones place

6 is in the Ones place

If it is 5 or greater we round it to the next ten, if it is 4 or less we keep it the same

6 is greater than 5

The number will be rounded to 430

You might be interested in

NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at Math.No guessing please.

SVETLANKA909090 [29]

Answer:

∠APC ≅ ∠DPB angles adjacent to the same angle are congruent to each other.

Explanation:

Because they share an angle created by P, they are adjacent.

I hope this helped :)

8 0

2 years ago

Will give brainliest answer

lidiya [134]

Answer:

I believe it's A)

Step-by-step explanation:

7 0

2 years ago

Iv) 6x+3y=6xy 2x + 4y= 5xy

Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5 - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

$y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}$

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0

2 years ago

The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.

Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg: c = a + 8

Use the Pythagorean Theorem:

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

Factors to:

(a-12)(a+4) = 0

a = 12, -4

Since we can't have a side of -4, a = 12

Shorter Leg = 12 inches

Longer Leg = 12 + 4 = 16 inches

Hypotenuse = 12 + 8 = 20 inches

6 0

3 years ago

A trapezoid has a height of 6 feet. The measures of the bases are 12 units and 18

Alik [6]

The area of this trapezoid is 90 square feet.

<h3>Explanation : </h3>

Before we know the answer, let's we know the formula first. The formula for count the area of trapezoid is :

$\boxed {\bold {A = \frac {(a+b) \times h}{2}}}$

If :

A = area of trapezoid
a = bottom bases of trapezoid
b = top bases of trapezoid
h = height of trapezoid

Okay, let's we count its :

We know that :

a = bottom bases of trapezoid = 18 feet
b = top bases of trapezoid = 12 feet
h = height of trapezoid = 6 feet

Question : A = area = ... ?

Answer :

$A = \frac {(a+b) \times h}{2} \\ A = \frac {(12+18) \times \cancel6}{\cancel2} \\ A = 30 \times 3 = 90 \: {ft}^{2}$

Subject : Mathematics

Keyword : Count The Area of a shape

8 0

2 years ago