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adoni [48]
4 years ago
12

Solve for x. 2x+3≤x−5   x≤8 x≤−2 x≤−8 x≤2

Mathematics
2 answers:
laiz [17]4 years ago
8 0

<em>Answer:</em>

<em>For this question the answer is : x ≤ − 8.</em>

<em>Step-by-step explanation:</em>

<em>For this question we have to solve for "x".</em>

<em>Now to solve for x we have to simplify both the sides of the inequality.</em>

<em>Then we have to isolate the variable.</em>

<em />

<em>And then we'll get our answer as : x ≤ − 8</em>

ladessa [460]4 years ago
4 0

Answer:

x ≤ -8

Step-by-step explanation:

To solve for x in the inequality given , we will follow the steps below;

2x+3≤x−5

First, subtract x from both-side of the inequality

2x- x+3 ≤ x-x−5

x + 3   ≤ −5

The next step to take is to subtract 3 from both-side of the equation

x + 3- 3   ≤ −5-3

(On the left-hand side of the inequality, 3 will be subtracted from 3, this gives us zero hence leaving us with just x, while on the right-hand side of the inequality  three will be subtracted from negative five, this will result to negative eight)

x ≤ -8

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i need help with math You reflect triangle PQR, with coordinates P(-4, -4), Q(-1, -3), and R(-3, -1), across the x-axis, across
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Answer:

After these reflections, the coordinates of P' will be P'(4,-4)

Step-by-step explanation:

<u><em>The question is</em></u>

After these reflections, the coordinates of P' will be?

we have

Triangle PQR, with coordinates P(-4, -4), Q(-1, -3), and R(-3, -1)

Part 1) Reflect triangle PQR across the x-axis

we know that

The rule of the reflection of a point across the x-axis is

(x,y) -----> (x,-y)

Applying the rule of the reflection across the x-axis at the coordinates of triangle PQR

P(-4, -4) -----> P'''(-4,4)

Q(-1, -3) -----> Q'''(-1, 3)

R(-3, -1) ----> R'''(-3, 1)

Part 2) Reflect triangle P'''Q'''R''' across the y-axis

we know that

The rule of the reflection of a point across the y-axis is

(x,y) -----> (-x,y)

Applying the rule of the reflection across the y-axis at the coordinates of triangle P'''Q'''R'''

P'''(-4,4) -----> P''(4,4)

Q'''(-1, 3) ---> Q''(1, 3)

R'''(-3, 1) ---> R''(3, 1)

Part 3) Reflect triangle P''Q''R'' across the x-axis again

we know that

The rule of the reflection of a point across the x-axis is

(x,y) -----> (x,-y)

Applying the rule of the reflection across the x-axis at the coordinates of triangle P''Q''R''

P''(4,4) ---->  P'(4,-4)

Q''(1, 3) ----> Q'(1, -3)

R''(3, 1) ----> R'(3, -1)

therefore

After these reflections, the coordinates of P' will be P'(4,-4)

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